Question

您好我试图在交易后减去用户信用额度但更新时出现问题。测试accepted_bidder = 15且客户信用额度为100.由于某种原因我更新时为-14而不是75个人都知道为什么会这样？

输出：

object（mysqli_result）＃2（5）{[＆＃34; current_field＆＃34;] =＆gt; INT（0） [＆＃34;场计数＆＃34;] =＆GT; int（1）[＆＃34; length＆＃34;] =＆gt; NULL [＆＃34; num_rows＆＃34;] =＆gt; INT（1） [＆＃34;类型＆＃34;] =＆GT; int（0）} int（15）注意：第19行的C：\ xampp \ htdocs \ payment2.php中无法将类mysqli_result的对象转换为int

<?php
session_start();
require 'config.php';


$id = $_SESSION['login_user'];
$jobid    = $_POST['job_id'];
$poster_id    = $_POST['poster_id'];
$accepted_bidder    = $_POST['accepted_bidder'];
$accepted_bid    = (int) $_POST['accepted_bid'];
$poster_id = $_POST['poster_id'];

$query = "SELECT credit FROM `customer` WHERE email_adress = '$id'";

$result = $conn->query($query);

var_dump($result);
var_dump($accepted_bid); 
$updated_credit = (int)$result - $accepted_bid;
//echo $updated_credit;


$query2   = "UPDATE job SET start_escrow = '1' WHERE job_id = '$jobid'";
$success = $conn->query($query2);

$query3   = " UPDATE customer SET credit = '$updated_credit' WHERE email_adress = '$id'";
$success3 = $conn->query($query3);



if (!$success) {
    die("Couldn't enter data: ".$conn->error);

}

echo "Thank You For Contacting Us <br>";
 //header("location: myjobs.php");



$conn->close();




?>

PHP信用更新错误金额

0 个答案: