Question

我有一个带有旧版UUID _id字段的MongoDB集合。

我可以通过传递UUID对象来检索pymongo的单个对象：

from uuid import UUID
from pymongo import MongoClient
client = MongoClient('localhost', 27017)
db = client[DB_NAME]
collection = db[COLLECTION_NAME]

one_ok = collection.find_one(
    filter={'_id': UUID('eedacde6-e241-4f37-a57d-c4e8eb6601a7')})
one_not_ok = collection.find_one(
    filter={'_id': 'eedacde6-e241-4f37-a57d-c4e8eb6601a7'})

print(one_ok is None)  # prints False
print(one_not_ok is None)  # prints True

然而，我似乎无法使用Eve获得个人资源。我得到了404：

http://localhost:5000/collection1/eedacde6-e241-4f37-a57d-c4e8eb6601b7

http://localhost:5000/collection1返回的列表提到的链接collection1/eedacde6-e241-4f37-a57d-c4e8eb6601b7似乎与返回404的网址相匹配：

<resource href="collection1" title="collection1">
    <link rel="parent" href="/" title="home"/>
    <_meta>
    <max_results>25</max_results>
    <page>1</page>
    <total>2</total>
    </_meta>
    <resource href="collection1/eedacde6-e241-4f37-a57d-c4e8eb6601b7" title="Collection1">
        <_created>Thu, 01 Jan 1970 00:00:00 GMT</_created>
        <_etag>9718572fe2d17b12358691602f6bd5f1ee345b06</_etag>
        <_id>eedacde6-e241-4f37-a57d-c4e8eb6601b7</_id>
        <_updated>Thu, 01 Jan 1970 00:00:00 GMT</_updated>
    </resource>
    <resource href="collection1/98c67ae6-ee7b-4bd3-9ec1-56b70fa2a9c7" title="Collection1">
        <_created>Thu, 01 Jan 1970 00:00:00 GMT</_created>
        <_etag>75c2451d19750e1007274315672bf893f9654273</_etag>
        <_id>98c67ae6-ee7b-4bd3-9ec1-56b70fa2a9c7</_id>
        <_updated>Thu, 01 Jan 1970 00:00:00 GMT</_updated>
    </resource>
</resource>

这是我在settings.py中的DOMAIN变量。我按照http://python-eve.org/tutorials/custom_idfields.html后的那种方式进行了设置。

DOMAIN = {
    'collection1': {
        'item_url': 'regex("[a-f0-9]{8}-?[a-f0-9]{4}-?4[a-f0-9]{3}-?[89ab][a-f0-9]{3}-?[a-f0-9]{12}")',
        'schema': {
            '_id': {'type': 'uuid'},
        },
    }
}

我怀疑这不起作用，因为UUID是＆＃39; Legacy UUIDs＆＃39;但我可能错了。

关于如何制作http://localhost:5000/collection1/eedacde6-e241-4f37-a57d-c4e8eb6601b7等网址的任何想法都会返回个人资源？

解决方法：破解夏娃

我能够通过黑客攻击来使它成功。必须为每个HTTP动词（GET，POST等）添加以下代码。

在eve/methods/get.py

def getitem_internal(resource, **lookup):
    """
    <...>
    """
    req = parse_request(resource)
    resource_def = config.DOMAIN[resource]
    embedded_fields = resolve_embedded_fields(resource, req)

    #### hack ###
    if '_id' in lookup:
        if 'schema' in resource_def and '_id' in resource_def['schema']:
            if resource_def['schema']['_id'].get('type') == 'uuid':
                lookup['_id'] = UUID(lookup['_id'])
    #### end of hack ###

    soft_delete_enabled = config.DOMAIN[resource]['soft_delete']
    if soft_delete_enabled:
        # GET requests should always fetch soft deleted documents from the db
        # They are handled and included in 404 responses below.
        req.show_deleted = True

    document = app.data.find_one(resource, req, **lookup)
    <...>

在Eve中检索具有旧UUID的各个资源

解决方法：破解夏娃

0 个答案: