Question

我的数据库中有2个表： -

pams_project表格包含表格project_name，dev_id（FK）
pams_developer表格具有表格结构developer_name，id（PK）

现在，我创建2个模型并在这两个表之间建立关系： -

Project.php模型

namespace App;

use Illuminate\Database\Eloquent\Model;
use App\Developer;

class Project extends Model
{
    protected $table = 'pams_project';
    protected $primaryKey = 'project_id';


    public function developer()
    {

        return $this->belongsTo(Developer::class,'dev_id','id');

    }
}

Developer.php型号

<?php

namespace App;

use Illuminate\Database\Eloquent\Model;
use App\Project;

class Developer extends Model
{
    //
    protected $table = 'pams_developer';
    protected $primaryKey = 'id';

    public function projects()
    {
        return $this->hasMany(Project::class,'dev_id','id');


    }
}

现在，我遇到了一个问题，我想从这个2模型中检索developer_name和project_name，如下面的SQL： -

 SELECT D.developer_name , P.project_name
 FROM pams_developer AS D
 JOIN pams_project AS P
 ON P.dev_id = D.id
 GROUP BY D.developer_name

但是我不知道怎么写这个2模型来从我的控制器中检索数据任何建议或解决方案都是适用的。

Answer 1

您应该检查laravel文档，了解如何使用雄辩的关系（以及热切的加载关系）：

https://laravel.com/docs/5.6/eloquent-relationships

对于你的（有点不清楚）的例子是：

$developers = App\Developer::with('projects')->get();

foreach($developers as $developer) {
    echo $developer->developer_name;

    foreach($developer->projects as $project) {
        echo $project->project_name;
}

在Eloquent ORM中加入2个表格

1 个答案: