Question

在我的Android应用程序中有2个编辑文本字段，它们是从日期和最后日期开始，我试图检查日期是有效还是无效我尝试使用此代码但它无法正常工作..错误在哪里我找不到请帮我纠正代码

advsearch.setOnClickListener(new View.OnClickListener() {
            @Override
            public void onClick(View v) {
                fromdate=fromed.getText().toString();
                todate=toed.getText().toString();

                matcher = Pattern.compile(DATE_PATTERN).matcher(fromdate);
                matcher = Pattern.compile(DATE_PATTERN).matcher(todate);


      if (!matcher.matches()) {
                    Toast.makeText(getApplicationContext(), "Invalid Date!", Toast.LENGTH_LONG).show();
                }
            }
        });

    }

搜索按钮Onclick代码

 public boolean validate(String date){

        matcher = pattern.matcher(date);

        if(matcher.matches()){

            matcher.reset();

            if(matcher.find()){

                String day = matcher.group(1);
                String month = matcher.group(2);
                int year = Integer.parseInt(matcher.group(3));

                if (day.equals("31") &&
                        (month.equals("4") || month .equals("6") || month.equals("9") ||
                                month.equals("11") || month.equals("04") || month .equals("06") ||
                                month.equals("09"))) {
                    return false; // only 1,3,5,7,8,10,12 has 31 days
                } else if (month.equals("2") || month.equals("02")) {
                    //leap year
                    if(year % 4==0){
                        if(day.equals("30") || day.equals("31")){
                            return false;
                        }else{
                            return true;
                        }
                    }else{
                        if(day.equals("29")||day.equals("30")||day.equals("31")){
                            return false;
                        }else{
                            return true;
                        }
                    }
                }else{
                    return true;
                }
            }else{
                return false;
            }
        }else{
            return false;
        }
    }
}
}

布尔类

GetType().GetProperties().Where(...).ToList();

Answer 1

为下面的数据验证制作单独的类..

public class DateValidator {

private Pattern pattern;
private Matcher matcher;

private static final String DATE_PATTERN =
        "(0?[1-9]|[12][0-9]|3[01])/(0?[1-9]|1[012])/((19|20)\\d\\d)";

public DateValidator() {
    pattern = Pattern.compile(DATE_PATTERN);
}

/**
 * Validate date format with regular expression
 *
 * @param date date address for validation
 * @return true valid date fromat, false invalid date format
 */
public boolean validate(final String date) {

    matcher = pattern.matcher(date);

    if (matcher.matches()) {

        matcher.reset();

        if (matcher.find()) {

            String day = matcher.group(1);
            String month = matcher.group(2);
            int year = Integer.parseInt(matcher.group(3));

            if (day.equals("31") &&
                    (month.equals("4") || month.equals("6") || month.equals("9") ||
                            month.equals("11") || month.equals("04") || month.equals("06") ||
                            month.equals("09"))) {
                return false; // only 1,3,5,7,8,10,12 has 31 days
            } else if (month.equals("2") || month.equals("02")) {
                //leap year
                if (year % 4 == 0) {
                    if (day.equals("30") || day.equals("31")) {
                        return false;
                    } else {
                        return true;
                    }
                } else {
                    if (day.equals("29") || day.equals("30") || day.equals("31")) {
                        return false;
                    } else {
                        return true;
                    }
                }
            } else {
                return true;
            }
        } else {
            return false;
        }
    } else {
        return false;
    }
}

}

然后点击按钮后点击下面的代码..

 fromdate = et.getText().toString();
            todate = et2.getText().toString();
            DateValidator dateValidator=new DateValidator();
            if (dateValidator.validate(fromdate)){
                Toast.makeText(getApplicationContext(),"Valid",Toast.LENGTH_SHORT).show();
            }
            else{
                Toast.makeText(getApplicationContext(),"InValid",Toast.LENGTH_SHORT).show();

            }

和edittext输入数据格式，如dd / mm / yyyy。

有关格式的更多信息，请参阅此链接 http://www.mkyong.com/regular-expressions/how-to-validate-date-with-regular-expression/

日期验证没有工作

1 个答案: