例如,我有一个按列表分组:
List<Cl> list = new List<Cl>()
{
new Cl() { vi = 1, vs = "q", am = 20 },
new Cl() { vi = 1, vs = "w", am = 30 },
new Cl() { vi = 2, vs = "w", am = 40 },
new Cl() { vi = 1, vs = "q", am = 50 }
};
groups = list.GroupBy(b => new { b.vi, b.vs }).ToList();
我希望通过汇总am字段得到合并列表:
Key am
[1, "q"] [70]
[1, "w"] [30]
[2, "w"] [40]
是否可以在没有词典或KeyValuePair的情况下实现它?
我将不胜感激任何帮助。
答案 0 :(得分:0)
您可以尝试这样的事情:
class Key
{
public int Vi { get; set; }
public string Vs { get; set; }
public Key(int vi, string vs)
{
Vi = vi;
Vs = vs;
}
}
var result = groups = list.GroupBy(b => new { b.vi, b.vs })
.Select(gr=> new { Key = Key(gr.vi,gr.vs)
, Value = gr.Sum(x=>x.am)})
.ToList();
答案 1 :(得分:0)
首先ARRAY : ["e", "s", "l", "e"]
ARRAY : ["s", "e", "l", "e"]
ARRAY : ["l", "e", "s", "e"]
ARRAY : ["e", "e", "s", "l"]
=> [["e", "s", "l", "e"], ["s", "e", "l", "e"], ["l", "e", "s", "e"], ["e", "e", "s", "l"]]
,然后GroupBy()
提升每组的Sum()
值
am
答案 2 :(得分:0)
试试这样:
<div class="col-xs-12 col-md-6 example-col">
<p>Custom defined format descriptions</p>
<kendo-dateinput format="G"
[formatPlaceholder]="{
year: 'y', month: 'M', day: 'd',
hour: 'h', minute: 'm', second: 's'
}"
></kendo-dateinput>
</div>