Question

$credentials = [
    'email' => Input::get('email'),
    'password' => Input::get('password'),
    'active'   => 1, //active
];

//Message if user in active user trying to logged in "This user is inactive mode conact to admin"

if (Auth::attempt($credentials, true)) {
    //logged in
}else{
    //Error
}

如果活跃用户中的用户尝试登录“此用户处于非活动状态，则会发送给管理员”，则应返回消息我们如何检查Auth :: attempts异常错误，请建议。

提前致谢

Answer 1

请像这样编码首先检查凭据是否正确，然后检查活动状态

 $credentials = [
        'email' => Input::get('email'),
        'password' => Input::get('password')
    ];


if (Auth::attempt($credentials)) {
    $user = Auth::user();
    if($user->active == 1) {
      // Login successfully
    } else {
      return error for inactive
    }
}else{
    //Error
}

Answer 2

$credentials = [
'email' => Input::get('email'),
'password' => Input::get('password'),
'active'   => 1, //active
];

//如果活跃用户中的用户尝试登录＆＃34;该用户是非活动模式与管理员合作＃34;

if (Auth::attempt($credentials)) {

       if(Auth::user()->active == 1) {
          // Login successfully
       } else {
          return back()->with('error','your account is inactive');
       }
}else{
  return back()->with('error','user is inactive');
}

现在在您的视图页面

  @if(Session::has('error'))
    {{Session::get('error')}}
  @endif

显示消息是用户在登录laravel时处于活动模式

2 个答案: