Question

我有一个for循环，我想显示此循环的每个结果的日期。我现在可以这样做，但它显示如下：

2018-04-19 12:00:00

我希望它显示如下：

19-04-2018

我能够定位子串并获得我想要的布局：

    forecastDayEl= sessionStorage.getItem("forecastDay");

    var objDay = JSON.parse(forecastDayEl);

objDay.forEach(function(entry) {

            var time = entry.substring(11, 13);
            var days = entry.substring(8, 10);
            var month = entry.substring(5, 7);
            var year = entry.substring(0, 4);

});

但我不知道如何将其添加到现有的for循环中：

var forecastLength;
var forecastText;
var g;

    forecastLength = objTemp.length;
    forecastText = "<div class='forecastList'>";
    for (g = 0; g < forecastLength; g++) {

        forecastText += "<ul>" + "<li class='forecastDay'>" + objDay[g] + "</li>" + "<li class='forecastTemp'>" + objTemp[g] + "</li>" + "<li class='forecastIcon'>" + "<img id='icon'" + "src='/weather/icons/" + objIcon[g] + ".png'" + "alt='Weather icon'>" + "</li>" + "</ul>";
    }
    forecastText += "</div>";

    //outputs result as list
    document.getElementById("forecastList").innerHTML = forecastText;

forecastDayEl正在输出：

["2018-04-19 12:00:00","2018-04-20 12:00:00","2018-04-21 12:00:00","2018-04-22 12:00:00","2018-04-23 12:00:00"]

objDay正在输出：

(5) ["2018-04-19 12:00:00", "2018-04-20 12:00:00", "2018-04-21 12:00:00", "2018-04-22 12:00:00", "2018-04-23 12:00:00"]
0
:
"2018-04-19 12:00:00"
1
:
"2018-04-20 12:00:00"
2
:
"2018-04-21 12:00:00"
3
:
"2018-04-22 12:00:00"
4
:
"2018-04-23 12:00:00"

var days输出：

如果我可以做以下事情，那么避免这种麻烦是理想的：

objDay[g].toDateString();

但是这不起作用：

objDay [g] .toDateString不是函数

Answer 1

使用The consul service terminated with the following service-specific error: Incorrect function.将.map转换为所需格式的字符串数组，然后使用转换后的数组：

＆＃13;

objDay

＆＃13;

Answer 2

将2018-04-19 12:00:00转换为19-04-2018的最简单方法是获取值并重新排序。有很多方法，例如。

＆＃13;

sudo -H pip3 install pip==8.1.1

＆＃13;

等等......

Answer 3

objDay.forEach(function(e, i) { 
    objDay[i] = (new Date(e)).toLocaleDateString('es-DO').replace(/\//g, '-'); 
});

日期数组.toDateString

3 个答案: