我在mySQL中有一个查询,但我不知道如何将格式转移到laravel。这是我的查询热线。
select T.id,t_id,T.name t_name, T.phone t_phone,
T.address t_address, T.Department t_department,
bgroup,sgroup,st_id,users.name st_name,
user_info.phone st_phone, user_info.address st_address,
user_info.Department st_department,st_hospital,st_code,
st_art,g_semester from
(SELECT user_group.id, t_id, name, phone, address,
Department, bgroup,sgroup,st_id,st_hospital,st_code,
st_art,g_semester FROM `user_group`
left join user_info on `t_id` = `school_id`
left join users on `t_id` =`s_id`) T
left join user_info on `st_id` = `school_id`
left join users on `st_id` =`s_id`
有人可以帮助我吗?如何将此查询转换为laravel格式? 我不知道如何从另一个查询中选择?
这 (SELECT user_group.id,t_id,姓名,电话,地址, 部门,bgroup,sgroup,st_id,st_hospital,st_code, st_art,g_semester FROM
上离开加入用户user_group
在t_id
=school_id
上左加入user_info 在t_id
=s_id
)T
答案 0 :(得分:1)
这是基础:
$from = DB::table('user_group')
->select('user_group.id', ...)
->leftJoin('user_info', 't_id', 'school_id')
->leftJoin(...);
DB::query()
->select('T.id as t_id', ...)
->fromSub($from, 'T')
->leftJoin('user_info', 'st_id', 'school_id')
->leftJoin(...)
->get();