基于状态和城市的SQL排名

Question

我有两个数据集。首先包含州名，城市名和其他包含温度信息。我怎样才能按州排名然后按城市排名超过温度？

select RANK() over(order by AVG(Average_Temp) desc) State_Rank_Temp, aqs_sites.State_Name, 
       RANK() over(partition by State_Name order by AVG(Average_Temp) desc) City_Rank, aqs_sites.City_Name, AVG(Temperature.Average_Temp) Average 
from aqs_sites INNER JOIN
    Temperature
     ON (aqs_sites.State_Code=Temperature.State_Code AND 
         aqs_sites.County_Code=Temperature.County_Code AND 
         aqs_sites.Site_Number=Temperature.Site_Num)
group by aqs_sites.City_Name, aqs_sites.State_Name;

Answer 1

Hmmmm。在进行排名之前，您需要州级的平均值。这是一种方法：

select s.State_Name, 
       s.City_Name,
       avg(t.Average_Temp) as average 
       rank() over (partition by s.State_Name order by avg(t.Average_Temp) desc) as City_Rank, 
       dense_rank() over (order by avg(state_average))
from aqs_sites s INNER JOIN
     (select t.*, avg(Average_Temp) over (partition by state_code) as state_average
      from Temperature t
     ) t
     ON s.State_Code = t.State_Code AND 
        s.County_Code = t.County_Code AND 
        s.Site_Number = t.Site_Num
group by s.City_Name, s.State_Name;