我希望获得两年之间的所有月份和两年之间的所有月份，所有数据都将汇总以获得每年的销售额。
这是我桌子的截图：
Screenshot
例如，我希望从2016年到2017年获得年度销售额，我需要将名称中2016年和2017年的所有列汇总到可以获得年度销售额的列。我知道这个表格不正常或正常。但这张桌子不是我的。
以下是获取两个日期之间月份的示例代码：
$start = new DateTime($_POST["start"]);
$end = new DateTime($_POST["end"]);
$smonth = (int)$start->format('Y')*12+(int)$start->format('n');
$emonth = (int)$end->format('Y')*12+(int)$end->format('n');
$firstmonth = min($smonth, $emonth);
$lastmonth = max($smonth, $emonth);
$months = array();
for ($i = $firstmonth; $i <= $lastmonth; $i++) {
$thism = new DateTime(sprintf('%04d-%02d-01', intdiv($i, 12), $i % 12));
$months[] = strtoupper($thism->format('M_Y'));
}
$m_total = implode(',', preg_replace('/^(.*)$/', 'SUM($1) AS $1', $months));
$m_average = implode(',', preg_replace('/^(.*)$/', 'AVG($1) AS $1', $months));
答案 0 :(得分：0)
在某些时候，你会后悔有一个很难查询的表格。我不知道你是否想为此利用动态sql，但以下可能有用。
MySQL 5.6架构设置：
CREATE TABLE Table1
(`DEC_2016` int, `JAN_2017` int, `FEB_2017` int, `MAR_2017` int, `APR_2017` int, `MAY_2017` int, `JUN_2017` int, `JUL_2017` int, `AUG_2017` int, `SEP_2017` int, `OCT_2017` int, `NOV_2017` int, `DEC_2017` int, `JAN_2018` int, `FEB_2018` int, `MAR_2018` int, `APR_2018` int, `MAY_2018` int, `JUN_2018` int, `JUL_2018` int, `AUG_2018` int, `SEP_2018` int, `OCT_2018` int, `NOV_2018` int, `DEC_2018` int, `JAN_2019` int)
;
INSERT INTO Table1
(`DEC_2016`, `JAN_2017`, `FEB_2017`, `MAR_2017`, `APR_2017`, `MAY_2017`, `JUN_2017`, `JUL_2017`, `AUG_2017`, `SEP_2017`, `OCT_2017`, `NOV_2017`, `DEC_2017`, `JAN_2018`, `FEB_2018`, `MAR_2018`, `APR_2018`, `MAY_2018`, `JUN_2018`, `JUL_2018`, `AUG_2018`, `SEP_2018`, `OCT_2018`, `NOV_2018`, `DEC_2018`, `JAN_2019`)
VALUES
(1000, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 100)
;
查询1 ：
set @start := '2017-01-15'
select concat(
'select '
,(select group_concat(' ', fn, ' as ', fn)
from (
select concat(upper(left(DATE_FORMAT(dt, "%M"),3)),'_',DATE_FORMAT(dt, "%Y")) fn
from (
SELECT
n, DATE_FORMAT(@start, '%Y-%m-01') + interval n MONTH AS dt
from (
select 0 n union all select 1 n union all select 2 n union all select 3 n union all select 4 n union all select 5 n union all select 6 n union all select 7 n union all select 8 n union all select 9 n union all select 10 n union all select 11
) d1
) d2
) d3
)
, ', ('
, replace(
(select trim(LEADING ' + ' from group_concat(' + ', fn))
from (
select concat(upper(left(DATE_FORMAT(dt, "%M"),3)),'_',DATE_FORMAT(dt, "%Y")) fn
from (
SELECT
n, DATE_FORMAT(@start, '%Y-%m-01') + interval n MONTH AS dt
from (
select 0 n union all select 1 n union all select 2 n union all select 3 n union all select 4 n union all select 5 n union all select 6 n union all select 7 n union all select 8 n union all select 9 n union all select 10 n union all select 11
) d1
) d2
) d3
), ',','')
, ') as Y1, '
, (select group_concat(' ', fn, ' as ', fn)
from (
select concat(upper(left(DATE_FORMAT(dt, "%M"),3)),'_',DATE_FORMAT(dt, "%Y")) fn
from (
SELECT
n, DATE_FORMAT(@start, '%Y-%m-01') + interval n MONTH AS dt
from (
select 12 n union all select 13 n union all select 14 n union all select 15 n union all select 16 n union all select 17 n union all select 18 n union all select 19 n union all select 20 n union all select 21 n union all select 22 n union all select 23
) d1
) d2
) d3
)
, ', ('
, replace(
(select trim(LEADING ' + ' from group_concat(' + ', fn))
from (
select concat(upper(left(DATE_FORMAT(dt, "%M"),3)),'_',DATE_FORMAT(dt, "%Y")) fn
from (
SELECT
n, DATE_FORMAT(@start, '%Y-%m-01') + interval n MONTH AS dt
from (
select 12 n union all select 13 n union all select 14 n union all select 15 n union all select 16 n union all select 17 n union all select 18 n union all select 19 n union all select 20 n union all select 21 n union all select 22 n union all select 23
) d1
) d2
) d3
), ',','')
, ') as Y2 '
, ' from table1'
) as the_sql
<强> Results ：
| the dynamically generated sql is:
|------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------|
| select JAN_2017 as JAN_2017, FEB_2017 as FEB_2017, MAR_2017 as MAR_2017, APR_2017 as APR_2017, MAY_2017 as MAY_2017, JUN_2017 as JUN_2017, JUL_2017 as JUL_2017, AUG_2017 as AUG_2017, SEP_2017 as SEP_2017, OCT_2017 as OCT_2017, NOV_2017 as NOV_2017, DEC_2017 as DEC_2017, (JAN_2017 + FEB_2017 + MAR_2017 + APR_2017 + MAY_2017 + JUN_2017 + JUL_2017 + AUG_2017 + SEP_2017 + OCT_2017 + NOV_2017 + DEC_2017) as Y1, JAN_2018 as JAN_2018, FEB_2018 as FEB_2018, MAR_2018 as MAR_2018, APR_2018 as APR_2018, MAY_2018 as MAY_2018, JUN_2018 as JUN_2018, JUL_2018 as JUL_2018, AUG_2018 as AUG_2018, SEP_2018 as SEP_2018, OCT_2018 as OCT_2018, NOV_2018 as NOV_2018, DEC_2018 as DEC_2018, (JAN_2018 + FEB_2018 + MAR_2018 + APR_2018 + MAY_2018 + JUN_2018 + JUL_2018 + AUG_2018 + SEP_2018 + OCT_2018 + NOV_2018 + DEC_2018) as Y2 from table1 |
<强> when that is executed, then: ：
| JAN_2017 | FEB_2017 | MAR_2017 | APR_2017 | MAY_2017 | JUN_2017 | JUL_2017 | AUG_2017 | SEP_2017 | OCT_2017 | NOV_2017 | DEC_2017 | Y1 | JAN_2018 | FEB_2018 | MAR_2018 | APR_2018 | MAY_2018 | JUN_2018 | JUL_2018 | AUG_2018 | SEP_2018 | OCT_2018 | NOV_2018 | DEC_2018 | Y2 |
|----------|----------|----------|----------|----------|----------|----------|----------|----------|----------|----------|----------|----|----------|----------|----------|----------|----------|----------|----------|----------|----------|----------|----------|----------|----|
| 1 | 1 | 1 | 1 | 1 | 1 | 1 | 1 | 1 | 1 | 1 | 1 | 12 | 1 | 1 | 1 | 1 | 1 | 1 | 1 | 1 | 1 | 1 | 1 | 1 | 12 |
答案 1 :(得分：0)
这可以给你你想要的东西。
$start = new DateTime('2016-04-20');
$end = new DateTime('2018-03-02');
$smonth = (int)$start->format('Y')*12+(int)$start->format('n');
$emonth = (int)$end->format('Y')*12+(int)$end->format('n');
$firstmonth = min($smonth, $emonth);
$lastmonth = max($smonth, $emonth);
$months = array();
$m_totals = array();
for ($m = $firstmonth; $m <= $lastmonth; $m++) {
$year = intdiv($m, 12);
$thism = new DateTime(sprintf('%04d-%02d-01', $year, $m % 12));
$months[] = strtoupper($thism->format('M_Y'));
if ($m % 12 == 0) {
// $m_totals[] = 'SUM(' . implode(',', $months) . ') AS SUM' . ($year - 1);
$m_totals[] = 'SUM(' . implode(') + SUM(', $months) . ') AS SUM' . ($year - 1);
$months = array();
}
}
if (count($months)) $m_totals[] = 'SUM(' . implode(') + SUM(', $months) . ') AS SUM' . $year;
$m_total = implode(', ', $m_totals);
echo "$m_total\n";
对于我使用的开始日期和结束日期，这将输出：
SUM(APR_2016) + SUM(MAY_2016) + SUM(JUN_2016) + SUM(JUL_2016) + SUM(AUG_2016) + SUM(SEP_2016) + SUM(OCT_2016) + SUM(NOV_2016) + SUM(DEC_2016) AS SUM2016,
SUM(JAN_2017) + SUM(FEB_2017) + SUM(MAR_2017) + SUM(APR_2017) + SUM(MAY_2017) + SUM(JUN_2017) + SUM(JUL_2017) + SUM(AUG_2017) + SUM(SEP_2017) + SUM(OCT_2017) + SUM(NOV_2017) + SUM(DEC_2017) AS SUM2017,
SUM(JAN_2018) + SUM(FEB_2018) + SUM(MAR_2018) AS SUM2018
要获得开始和结束年份的所有月份，只需更改以下行：
$smonth = (int)$start->format('Y')*12+1;
$emonth = (int)$end->format('Y')*12+12;