Question

我正在尝试使用swift循环嵌套JSON，但我能够检索未嵌套的记录。我无法检索嵌套记录。我也尝试过valueForKeyPath，但它不起作用。

这就是我现在所做的：

这是JSON：

[  
   {  
      "id":"001",
      "firstName":"Fred",
      "lastName":"Blogs",
      "role":"Producer"
   },
   {  
      "teamName":"A",
      "members":[  
         {  
            "id":"002",
            "firstName":"Michael",
            "lastName":"Right",
            "role":"Cook"
         },
         {  
            "id":"003",
            "firstName":"James",
            "lastName":"Brown",
            "role":"Bus Driver"
         },
         {  
            "id":"004",
            "firstName":"Liam",
            "lastName":"Nelson",
            "role":"Actor"
         },
         {  
            "id":"005",
            "firstName":"Chris",
            "lastName":"Tucker",
            "role":"Actor"
         },
         {  
            "id":"006",
            "firstName":"Richard",
            "lastName":"Burton",
            "role":"Golfer"
         },
         {  
            "id":"007",
            "firstName":"Matt",
            "lastName":"Smith",
            "role":"Care Taker"
         }
      ]
   },
   {  
      "teamName":"B",
      "members":[  
         {  
            "id":"008",
            "firstName":"Mark",
            "lastName":"Jones",
            "role":"Script Writter"
         },
         {  
            "id":"009",
            "firstName":"Hello",
            "lastName":"World",
            "role":"Tester"
         }
      ]
   }
]

这是Swift代码：

func getJSON() {

    guard let url = URL(string: "http://www.somejson.json") else { return }
    do {
        let data = try Data(contentsOf: url)
        let json = try? JSONSerialization.jsonObject(with: data, options: .allowFragments) as AnyObject

        guard let array = json as?[[String: Any]] else { return }

        var teams = [Team]()
        var team: Team
        var i = 0

        for items in array {

            team = Team()


            if let id  = items["id"] as? String {
                team.id = id
                print("id", team.id)
            }

            if let firstName  = items["firstName"] as? String {
                team.firstName = firstName
                print("FirstName", team.firstName)
            }


            if let lastName  = items["lastName"] as? String {
                team.lastName = lastName
                print("LastName", team.lastName)
            }


            if let role  = items["role"] as? String {
                team.role = role
                print("Role", team.role)
            }


            if let profileImageURL  = items["profileImageURL"] as? String {
                team.profileImageURL = profileImageURL
                print("ProfileImageURL", team.profileImageURL)
            }


            if let teamName  = items["teamName"] as? String {

                print("TeamName", teamName)

                //if let id = json?.value(forKeyPath:"members.id") {
                  //  print("Test", id)
                //}

            }

            teams.append(team)

    }

        print("Count", teams.count)

    } catch {

    }
}

Answer 1

使用Swift Codable协议是可行的方法。甚至还有Custom components等在线工具可以帮助您从JSON生成Swift代码。

解析JSON的示例代码：

// To parse the JSON, add this file to your project and do:
//
//   let teams = try? JSONDecoder().decode([Team].self, from: jsonData)

import Foundation

typealias Team = [TeamElement]

struct TeamElement: Codable {
    let id, firstName, lastName, role: String?
    let teamName: String?
    let members: [Member]?
}

struct Member: Codable {
    let id, firstName, lastName, role: String
}

Answer 2

您忘了允许JSON结构包含包含团队成员的项目“成员”这一事实。

func getJSON() {

    guard let url = URL(string: "http://www.somejson.json") else { return }
    do {
        let data = try Data(contentsOf: url)
        let json = try? JSONSerialization.jsonObject(with: data, options: .allowFragments) as AnyObject

        guard let array = json as?[[String: Any]] else { return }

        var teams = [Team]()
        for teamJson in array {
            var team = Team()

            if let members = teamJson["members"] as? [[String: Any]] {
                team.teamName = teamJson["teamName"] as! String
                for memberJson in members {
                    var member = Member()

                    if let id  = memberJson["id"] as? String {
                        member.id = id
                        print("id", member.id)
                    }

                    if let firstName  = memberJson["firstName"] as? String {
                        member.firstName = firstName
                        print("FirstName", member.firstName)
                    }


                    if let lastName  = memberJson["lastName"] as? String {
                        member.lastName = lastName
                        print("LastName", member.lastName)
                    }


                    if let role  = memberJson["role"] as? String {
                        member.role = role
                        print("Role", member.role)
                    }

                    team.members.append(member)
                }
            }

            teams.append(team)
        }

        print("Count", teams.count)

    } catch {
    }

}

您还必须编写代码来处理不在团队中的异常值producer，但我相信您可以自己解决这个问题。：）

Swift 3.0中的复杂嵌套JSON

2 个答案: