Question

目前我有一个数组：

$movie_seat = "seat1, seat2, seat3, seat4";

foreach($movie_seat as $keys =>$values)
        {
        $movie_id = $values["movie_id"];
        $movie_seats = $values["movie_seats"];

            $query = "INSERT INTO `testing` (`movie_id`,`movie_seat`) VALUES ('$movie_id ','$movie_seats')" ;

            $addmoviequery = mysqli_query($conn,$query);
            if(!$addmoviequery){
                die("QUERY FAILED".mysqli_error($conn));

            }

从数组

，我将得到以下结果存储在database.It将整个数组存储到movie_seat列。

+-----------------+-------------------------------+
| movie_id        | movie_seat                    |
+-----------------+-------------------------------+
| movie01         | seat1, seat2, seat3           |
| movie02         | seat5,seat6                   |
+-----------------+-------------------------------+

但是，我想记录到不同列的数据库

我想要的结果：

 +-----------------+-------+-------+-------+-------+-------+-------+
 | movie_id        | seat1 | seat2 | seat3 | seat4 | seat5 | seat6 |
 +-----------------+-------+-------+-------+-------+-------+-------+
 | movie01         | booked|booked |booked |       |       |       |
 | movie02         |       |       |       |       |booked |booked |
 +-----------------+-------+-------+-------+-------+-------+-------+

我尝试使用爆炸功能，但会显示

警告：在C：\
中为foreach（）提供的参数无效

Answer 1

您正在做的事情中存在多个错误。

$movie_seat = "seat1, seat2, seat3, seat4";

这不是array 。这是string。

你必须explode将它放入一个数组中，如下所示：

$seats = explode(",", $movie_seat);

这将创建一个名为array的{{1}}字符串，其中$seats等于＆＃34; seat1＆＃34;等...

然后，您需要使用您创建的新数组$seats[0]，而不是旧变量。像这样：

foreach

PHP存储数组进入单独的列

1 个答案: