我有一个名为XML_INFRASTRUCTURE
的表,其设计如下:
COLUMN_NAME | DATA_TYPE | NULLABLE
-------------|--------------------|--------
XMLI_ID | NUMBER(10,0) | No
FILENAME | VARCHAR2(255 CHAR) | Yes
LAST_VERSION | DATE | Yes
XML_RAW | CLOB | Yes
在此表中,我将通过FTP接收的所有XML文件存储为XMLTYPE。我使用XMLTABLE来获取信息,一切正常,直到我开始加入表格。
在XML_INFRASTRUCTURE
我有以下数据:
XMLI_ID | FILENAME | LAST_VERSION | XML_RAW
--------|--------------|--------------|--------------------------------
1 | ptcar | 07-JAN-18 | <?xml version="1.0" encoding="ISO-8859-1"?><cern:ptcars creationDate="2018-03-16T19:35:54" xmlns:cern="http://www.website.com/Infrastructure" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://www.website.com/Infrastructure ../ns/infrastructure.xsd"><cern:ptcar id="1" validFromDate="1996-06-02" validToDate="2007-12-08" ....>
2 | ptrefColumn | 07-JAN-18 | <?xml version="1.0" encoding="ISO-8859-1"?><cern:ptrefColumns creationDate="2018-03-20T11:33:21" xmlns:cern="http://www.website.com/Infrastructure" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://www.website.com/Infrastructure ../ns/infrastructure.xsd"><cern:ptrefColumn id="279" validFromDate="1998-04-01" validToDate="2001-06-11" ....>
3 | ptref | 07-JAN-18 | <?xml version="1.0" encoding="ISO-8859-1"?><cern:ptrefs creationDate="2018-03-20T11:33:05" xmlns:cern="http://www.website.com/Infrastructure"xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://www.website.com//Infrastructure ../ns/infrastructure.xsd"><cern:ptref id="232" validFromDate="1998-04-01" validToDate="2001-06-11" ....>
接下来我有以下要求:
给定值:ptrefId和givenDate
select a.longNameFrench , a.longNameDutch
from ptcar as a,
ptrefColumn as b,
ptref as c
where c.id = ptrefId
and b.id = c.ptrefColumnId
and a.id = b.ptcarId
and a.validFromDate <= givenDate
and a.validToDate >= givenDate
and b.validFromDate <= givenDate
and b.validToDate >= givenDate
and c.validFromDate <= givenDate
and c.validToDate >= givenDate
知道这一点,我尝试用XMLTABLE获取XML,但我不知道如何启动和运行连接。正如你所看到的,我尝试将XMLTABLE链接起来,但就像这样,它已经运行了一个多小时了。
SELECT X.LongNameFrench, X.LongNameDutch
FROM XML_Infrastructure,
XMLTABLE(
'$d/*:ptcars/*:ptcar'
PASSING XMLTYPE(XML_Infrastructure.XML_RAW) as "d"
COLUMNS
Id VARCHAR2(10) PATH '@*:id',
LongNameFrench VARCHAR2(60) PATH '@*:longNameFrench',
LongNameDutch VARCHAR2(60) PATH '@*:longNameDutch',
ValidFromDate VARCHAR2(10) PATH '@*:validFromDate',
ValidToDate VARCHAR2(10) PATH '@*:validToDate'
) AS X,
XMLTABLE(
'$d/*:ptrefColumns/*:ptrefColumn'
PASSING XMLTYPE(XML_Infrastructure.XML_RAW) as "d"
COLUMNS
Id VARCHAR2(10) PATH '@*:id',
ValidFromDate VARCHAR2(10) PATH '@*:validFromDate',
ValidToDate VARCHAR2(10) PATH '@*:validToDate'
) AS Y,
XMLTABLE(
'$d/*:ptrefs/*:ptref'
PASSING XMLTYPE(XML_Infrastructure.XML_RAW) as "d"
COLUMNS
Id VARCHAR2(10) PATH '@*:id',
ValidFromDate VARCHAR2(10) PATH '@*:validFromDate',
ValidToDate VARCHAR2(10) PATH '@*:validToDate'
) AS Z
WHERE Z.Id = '512'
AND FILENAME = 'ptcar';
建议非常欢迎! (抱歉信息过载)
答案 0 :(得分:1)
您正在从同一个XML文档创建三个XMLTable结果X,Y和Z,并且只有ptcar
节点 - 因此Y和Z找不到任何数据(因为没有节点匹配)那些XPath)。
鉴于三个XML文档之间的相似性,并假设您显示的ID节点都应该是相同的值(在示例数据中不是这种情况),您可以使用单个XMLTable来提取所有文件中的所有相关数据:
SELECT X.Name, X.Id, X.ValidFromDate, X.ValidToDate, X.LongNameFrench, X.LongNameDutch
FROM XML_Infrastructure
CROSS JOIN XMLTABLE(
'$d/*/*'
PASSING XMLTYPE(XML_Infrastructure.XML_RAW) as "d"
COLUMNS
Name VARCHAR2(10) PATH './local-name()',
Id NUMBER PATH '@*:id',
LongNameFrench VARCHAR2(60) PATH '@*:longNameFrench',
LongNameDutch VARCHAR2(60) PATH '@*:longNameDutch',
ValidFromDate DATE PATH '@*:validFromDate',
ValidToDate DATE PATH '@*:validToDate'
) X;
这使用通配符来获取任何子节点,但如果您还有其他未显示的类型,则可以对其进行过滤。它还会添加一个name
列,以便您可以分辨每行来自哪个文档(或者如果您愿意,可以包含文件名)。它将为所有三个中不存在的属性提供空值。
然后在CTE中使用它并将其连接到自身两次:
WITH cte AS (
SELECT X.Name, X.Id, X.ValidFromDate, X.ValidToDate, X.LongNameFrench, X.LongNameDutch
FROM XML_Infrastructure
CROSS JOIN XMLTABLE(
'$d/*/*'
PASSING XMLTYPE(XML_Infrastructure.XML_RAW) as "d"
COLUMNS
Name VARCHAR2(30) PATH './local-name()',
Id NUMBER PATH '@*:id',
LongNameFrench VARCHAR2(60) PATH '@*:longNameFrench',
LongNameDutch VARCHAR2(60) PATH '@*:longNameDutch',
ValidFromDate DATE PATH '@*:validFromDate',
ValidToDate DATE PATH '@*:validToDate'
) AS X
)
select a.longNameFrench, a.longNameDutch
from cte a
join cte b on b.id = a.id
join cte c on c.id = b.id
where c.name = 'ptref'
and b.name = 'ptrefColumn'
and a.name = 'ptcar'
and c.id = ptrefId
and a.validFromDate <= givenDate
and a.validToDate >= givenDate
and b.validFromDate <= givenDate
and b.validToDate >= givenDate
and c.validFromDate <= givenDate
and c.validToDate >= givenDate;
这有点类似于为每种文档类型创建查询的视图,然后加入这些视图,但不需要任何新的永久对象。
将您的部分样本数据放在另一个CTE中,并将所有ID设置为512并在ptcar
中添加缺少的名称:
with XML_INFRASTRUCTURE (XMLI_ID, FILENAME, LAST_VERSION, XML_RAW) as (
select cast (1 as number(2,0)), cast('ptcar' as varchar2(255)), date '2018-01-07', to_clob('<?xml version="1.0" encoding="ISO-8859-1"?>
<cern:ptcars creationDate="2018-03-16T19:35:54" xmlns:cern="http://www.website.com/Infrastructure" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://www.website.com/Infrastructure ../ns/infrastructure.xsd">
<cern:ptcar id="512" validFromDate="1996-06-02" validToDate="2007-12-08" longNameFrench="Jean Dupont" longNameDutch="Jan Jansen"/>
</cern:ptcars>') from dual
union all select 2, 'ptrefColumn', date '2018-01-07', to_clob('<?xml version="1.0" encoding="ISO-8859-1"?>
<cern:ptrefColumns creationDate="2018-03-20T11:33:21" xmlns:cern="http://www.website.com/Infrastructure" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://www.website.com/Infrastructure ../ns/infrastructure.xsd">
<cern:ptrefColumn id="512" validFromDate="1998-04-01" validToDate="2001-06-11" />
</cern:ptrefColumns>') from dual
union all select 3, 'ptref', date '2018-01-07', to_clob('<?xml version="1.0" encoding="ISO-8859-1"?>
<cern:ptrefs creationDate="2018-03-20T11:33:05" xmlns:cern="http://www.website.com/Infrastructure" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://www.website.com//Infrastructure ../ns/infrastructure.xsd">
<cern:ptref id="512" validFromDate="1998-04-01" validToDate="2001-06-11" />
</cern:ptrefs>') from dual
),
cte AS (
SELECT X.Name, X.Id, X.ValidFromDate, X.ValidToDate, X.LongNameFrench, X.LongNameDutch
FROM XML_Infrastructure
CROSS JOIN XMLTABLE(
'$d/*/*'
PASSING XMLTYPE(XML_Infrastructure.XML_RAW) as "d"
COLUMNS
Name VARCHAR2(30) PATH './local-name()',
Id NUMBER PATH '@*:id',
LongNameFrench VARCHAR2(60) PATH '@*:longNameFrench',
LongNameDutch VARCHAR2(60) PATH '@*:longNameDutch',
ValidFromDate DATE PATH '@*:validFromDate',
ValidToDate DATE PATH '@*:validToDate'
) AS X
)
select a.longNameFrench, a.longNameDutch
from cte a
join cte b on b.id = a.id
join cte c on c.id = b.id
where c.name = 'ptref'
and b.name = 'ptrefColumn'
and a.name = 'ptcar'
and c.id = 512
and a.validFromDate <= date '2001-01-01'
and a.validToDate >= date '2001-01-01'
and b.validFromDate <= date '2001-01-01'
and b.validToDate >= date '2001-01-01'
and c.validFromDate <= date '2001-01-01'
and c.validToDate >= date '2001-01-01';
给出
LONGNAMEFRENCH LONGNAMEDUTCH
------------------------------------------------------------ ------------------------------------------------------------
Jean Dupont Jan Jansen
答案 1 :(得分:0)
选择(或创建视图),如下所示:
CREATE VIEW ptcar AS
SELECT Id, LongNameFrench, LongNameDutch,
TO_DATE(x.ValidFromDate, 'YYYY-MM-DD') as ValidFromDate,
...
FROM XML_Infrastructure,
XMLTABLE(
'$d/*:ptcars/*:ptcar'
PASSING XMLTYPE(XML_Infrastructure.XML_RAW) as "d"
COLUMNS
Id VARCHAR2(10) PATH '@*:id',
LongNameFrench VARCHAR2(60) PATH '@*:longNameFrench',
LongNameDutch VARCHAR2(60) PATH '@*:longNameDutch',
ValidFromDate VARCHAR2(10) PATH '@*:validFromDate',
ValidToDate VARCHAR2(10) PATH '@*:validToDate'
) as x;
CREATE VIEW ptrefColumn AS
SELECT Id,
TO_DATE(x.ValidFromDate, 'YYYY-MM-DD') as ValidFromDate,
...
FROM XML_Infrastructure,
XMLTABLE(
'$d/*:ptrefColumns/*:ptrefColumn'
PASSING XMLTYPE(XML_Infrastructure.XML_RAW) as "d"
COLUMNS
Id VARCHAR2(10) PATH '@*:id',
ValidFromDate VARCHAR2(10) PATH '@*:validFromDate',
ValidToDate VARCHAR2(10) PATH '@*:validToDate'
) as x
之后,您可以按照问题中的说明直接加入。
注意,为什么将XML_RAW
存储为CLOB
而不是XMLTYPE
?