Question

我有两张桌子加入了他们。现在，我需要从连接的表中选择2列，一个应该是列，如果案件有被告和原告，那么它应该显示OK，如果只有被告然后def，原告然后pltf，如果它们都没有那么。< / p>

我基本上有这种表：

export class Sum extends Component {
constructor(props) {
    super(props)
    this.state = {
        sum: 0, buttonClicked:[false,false,false]
    }
}

handleClick(buttonNumber) {

  if(this.state.buttonClicked[buttonNumber-1]){
   this.setState({sum:this.state.sum-1})
  else
   this.setState({sum:this.state.sum+1})

  let x = this.state.buttonClicked; 
  x[buttonNumber-1] = true;   //for updating buttonClicked array
  this.setState({buttonClicked:x})

}

render() {
    return (
        <div>
            <button onClick={this.handleClick.bind(this,1)}>button1</button>
            <button onClick={this.handleClick.bind(this,2)}>button2</button>
            <button onClick={this.handleClick.bind(this,3)}>button3</button>
        </div>
    )
}

我需要这个：

Personid#    Case#       Role        CaseType
----------------------------------------------
cg902        CB190       Plaintiff   Civil
cg903        CB190       Defendant   Civil
cg904        CB191       Plaintiff   Civil
cg905        CB192       Defendant   Civil
cg906        CB193        none       Civil

我真的很感激。

Answer 1

将table_name替换为您的表名
此查询将解决您的要求：

select distinct y.case#,
case 
when x.role='Plaintiff' and y.cnt=1 then 'PLTF'
when x.role='Defendant' and y.cnt=1 then 'Def'
when x.role='none' and y.cnt=1 then 'NONE'
when y.cnt=2 then
  case
  when exists(select 1 from TABLE_NAME where role='Plaintiff' and CASE#=y.case#) and
  exists(select 1 from TABLE_NAME where role='Defendant' and CASE#=y.case#)
  then 'OK'
  end
end 
from 
(select case#,
count(case#) as cnt
from TABLE_NAME
group by case#
order by case#) y, TABLE_NAME x
where x.case#=y.case#
order by y.case#
;

Answer 2

这样的事情（修复案例和 personID 问题）：

SQL> with test (ccase, crole) as
  2    (select 'cb190', 'plaintiff' from dual union
  3     select 'cb190', 'defendant' from dual union
  4     select 'cb191', 'plaintiff' from dual union
  5     select 'cb192', 'defendant' from dual union
  6     select 'cb193', 'none'      from dual
  7    ),
  8  inter as
  9    (select ccase, min(crole) minrole, max(crole) maxrole
 10     from test
 11     group by ccase
 12    )
 13  select ccase,
 14    case when minrole <> maxrole then 'ok'
 15         when minrole =  maxrole and minrole = 'plaintiff' then 'pltf'
 16         when minrole =  maxrole and minrole = 'defendant' then 'def'
 17         else 'none'
 18    end anycolname
 19  from inter
 20  order by ccase;

CCASE ANYC
----- ----
cb190 ok
cb191 pltf
cb192 def
cb193 none

SQL>

sql，oracle，数据库

2 个答案: