我尝试使用filedialog
方法打开所有选定的文件,然后将所选路径中的所有内容复制到当前工作簿。第一个路径文件设法复制所有内容,当它到达第二个时,错误:
"你不能粘贴在这里因为复制区域,只选择粘贴区域中的一个单元格。"
以下是我的代码:
Sub Select_File_Click()
Dim lngCount As Long
Dim cl As Range
Dim c2 As Range
Dim ItemType As String
ThisWorkbook.Sheets("Sheet1").Range("A:D").ClearContents
Set cl = ActiveSheet.Cells(1, 3)
' Open the file dialog
With Application.FileDialog(msoFileDialogOpen)
.AllowMultiSelect = True
.Filters.Clear
.Filters.Add "comma-separated values", "*.csv"
.InitialFileName = "*" & ItemType & "*.*"
.InitialView = msoFileDialogViewDetails
.Show
For lngCount = 1 To .SelectedItems.Count
' Add Hyperlinks
cl.Worksheet.Hyperlinks.Add _
Anchor:=cl, Address:=.SelectedItems(lngCount), _
TextToDisplay:=.SelectedItems(lngCount)
' Add file name
'cl.Offset(0, 1) = _
' Mid(.SelectedItems(lngCount), InStrRev(.SelectedItems(lngCount), "\") + 1)
' Add file as formula
cl.Offset(0, 1).FormulaR1C1 = _
"=TRIM(RIGHT(SUBSTITUTE(RC[-1],""\"",REPT("" "",99)),99))"
Set cl = cl.Offset(1, 0)
Set c2 = cl.Offset(0, 1)
Next lngCount
Sheets(1).Cells(1, 1) = .SelectedItems.Count
End With
End Sub
Sub All_data_Click()
Dim Count As Integer
Dim iLast As Long
ThisWorkbook.Sheets("Copy").Range("A1:AZ5000").ClearContents
Count = ThisWorkbook.Sheets(1).Cells(1, 1)
iLast = 1
For i = 1 To Count
pth = ThisWorkbook.Sheets("Sheet1").Cells(i, 3).Value 'Select folder path
Set LookupWB = Workbooks.Open(Filename:=pth)
Set sourceColumn1 = ThisWorkbook.Sheets("Copy")
Set Source = ActiveWorkbook.Sheets(1)
Set sourceColumn1 = Source.Columns("A:AZ")
Set targetColumn1 = ThisWorkbook.Worksheets("Copy").Rows(iLast)
sourceColumn1.Copy Destination:=targetColumn1 <---Error Here:
iLast = iLast + sourceColumn1.Range("A" & Rows.Count).End(xlUp).Row
Next i
End Sub
有什么想法可以解决这个问题吗?我已经迷路了。
答案 0 :(得分:1)
如果我理解你想要做什么,我建议采用一种稍微不同的方法:
src/Vector.hs:36:42: error:
• Could not deduce (Applicative (Vec c))
arising from a use of ‘sequenceA’
from the context: Num a
bound by the instance declaration at src/Vector.hs:35:10-37
• In the first argument of ‘vmult’, namely ‘(sequenceA x)’
In the second argument of ‘($)’, namely ‘(vmult (sequenceA x) y)’
In the expression: Matrix $ (vmult (sequenceA x) y)
|
36 | Matrix x . Matrix y = Matrix $ (vmult (sequenceA x) y)
| ^^^^^^^^^^^