Question

我试图通过SQL Server中的SQL实现以下目的。

我有一个源表，其中包含以下记录：

screenshot of source and target data

我应该总是检索RCD 6和7条记录（如果存在）
对于RCD 8和9，我需要检查相同的PKey：
- 如果Rkey相同，如果是，那么我只需要检索任何记录

RCD

PKey

Rkey

我尝试过这样做，但我不知道如何做到这一点，任何人都可以建议如何在SQL for SQL Server中实现这一点。

Answer 1

如果我理解正确，您可以使用窗口函数来获取所需的基本信息。其余的只是逻辑：

select t.*
from (select t.*,
             min(rkey) over (partition by rcd, pkey) as min_rkey,
             max(rkey) over (partition by rcd, pkey) as max_rkey,
             row_number() over (partition by rcd, pkey, rkey order by rkey) as seqnum
      from t
     ) t
where rcd in (6, 7) or
      ( (rcd in (8, 9) and min_rkey = max_rkey and seqnum = 1) or
        (rcd in (8, 9) and min_rkey <> max_rkey)
      );

编辑：

我怀疑在8/9条件下你需要的不仅仅是pkey：

select t.*
from (select t.*,
             min(rkey) over (partition by rcd, pkey) as min_rkey,
             max(rkey) over (partition by rcd, pkey) as max_rkey,
             row_number() over (partition by rcd, pkey, rkey order by rkey) as seqnum,
             count(*) over (partition by rcd, pkey) as cnt
      from t
     ) t
where rcd in (6, 7) or
      ( (rcd in (8, 9) and cnt > 1 and min_rkey = max_rkey and seqnum = 1) or
        (rcd in (8, 9) and cnt > 1 and min_rkey <> max_rkey)
      );

Answer 2

如果我理解正确，这就是你要找的东西：

SELECT RAKey, RCD, Pkey, Rkey, Akey
    FROM Source s
        WHERE s.RCD IN (6,7)
UNION
SELECT RAKey, RCD, Pkey, Rkey, Akey FROM
(SELECT 
row_number() over(partition by Pkey order by newid()) as rowID,
*
    FROM Source s2
        WHERE RCD IN (8,9)
        AND (EXISTS (SELECT TOP 1 1 FROM Source WHERE Pkey = s2.Pkey AND s2.RCD = 8 AND RCD = 9 AND RKey = s2.Rkey)
        OR EXISTS (SELECT TOP 1 1 FROM Source WHERE Pkey = s2.Pkey AND s2.RCD = 9 AND RCD = 8 AND RKey = s2.Rkey))
        ) s2
        WHERE rowID = 1
UNION
SELECT RAKey, RCD, Pkey, Rkey, Akey
    FROM Source s3
        WHERE RCD IN (8,9)
        AND (EXISTS (SELECT TOP 1 1 FROM Source WHERE Pkey = s3.Pkey AND s3.RCD = 8 AND RCD = 9 AND RKey <> s3.Rkey)
        OR EXISTS (SELECT TOP 1 1 FROM Source WHERE Pkey = s3.Pkey AND s3.RCD = 9 AND RCD = 8 AND RKey <> s3.Rkey))

此外，您的目标插图与您在下面的标准相矛盾：

对于RCD 8和9对于相同的PKey，如果Rkey不同，那么我需要检索两者。

据推测，由于RKey的不同如下所示，因此可以显示401和501：

enter image description here

Answer 3

SELECT * 
FROM [SOURCE] WHERE RCD IN (6,7)

UNION ALL
SELECT H.RAKEY,H.RCD,H.pkey,H.rkey
FROM
(
 SELECT ROW_NUMBER()OVER (PARTITION BY PKEY,rkey,Value ORDER BY RAKEY) 
 RNO,A.*
 FROM
 (
   SELECT  H.RAKEY,H.RCD,H.pkey,H.rkey,CASE WHEN H.RAKEY < K.RAKEY THEN 
   H.RAKEY ELSE K.RAKEY END Value
   FROM [SOURCE] H
   LEFT JOIN [SOURCE] K
   ON H.pkey = K.pkey AND H.rkey = K.rkey AND H.RCD <> K.RCD AND K.RCD IN 
   (8,9)
   WHERE H.RCD IN (8,9) 
  )A
 )H WHERE H.RNO = 1
 ORDER BY 1`

Answer 4

SELECT H.RAKEY,H.RCD,H.pkey,H.rkey
FROM
 (
   SELECT ROW_NUMBER()OVER (PARTITION BY PKEY,rkey,Value ORDER BY RCD) 
   RNO,A.*
   FROM
  (
    SELECT  H.RAKEY,H.RCD,H.pkey,H.rkey,MIN(H.RCD) OVER (Partition by 
     H.PKey,K.rkey) Value
      FROM [SOURCE] H
      LEFT JOIN [SOURCE] K
      ON H.pkey = K.pkey AND H.rkey = K.rkey AND H.RCD <> K.RCD AND K.RCD IN 
      (6,8,9)
     WHERE H.RCD IN (6,8,9) 
   )A
   )H WHERE H.RNO = 1

嗨Gaur，我希望上面的查询适用于您的问题“我想要做的是，如果RCD 6和RCD 8和9的PKey和RKey值相同，我想保留RCD6的详细信息并放弃休息细节。“

SQL到条件检索记录 - SQL Server

4 个答案: