Question

以下是我的代码。我一直在尝试修复代码以对哈希（SHA-1）执行字典攻击，我得到以下结果。附：我是编码的初学者。

import hashlib
import random
#plug in the hash that needs to be cracked
hash_to_crack = "5baa61e4c9b93f3f0682250b6cf8331b7ee68fd8"
#direct the location of the dictionary file
dict_file = "C:/Users/kiran/AppData/Local/Programs/Python/Python37/dictionary.txt"

def main():
    with open(dict_file) as fileobj:
        for line in fileobj:
            line = line.strip()
            if hashlib.sha1(line.encode()).hexdigest() == hash_to_crack:
                print ("The password is %s") % (line);
                return ""
    print ("Failed to crack the hash!")
    return ""


if __name__ == "__main__":
    main()

结果：

RESTART: C:/Users/kiran/AppData/Local/Programs/Python/Python37/Codes/datest1.py
The password is %s
Traceback (most recent call last):
  File "C:/Users/kiran/AppData/Local/Programs/Python/Python37/Codes/datest1.py", line 20, in <module>
    main()
  File "C:/Users/kiran/AppData/Local/Programs/Python/Python37/Codes/datest1.py", line 13, in main
    print ("The password is %s") % (line);
TypeError: unsupported operand type(s) for %: 'NoneType' and 'str'

Answer 1

您正在使用Python 3，其中print是一个函数。这一行：

print ("The password is %s") % (line)

使用参数print调用函数"The password is %s"。该函数返回None。然后None % (line)会显示您看到的错误消息。

大多数惯用语是用这种方式写行：

print("The password is", line)

其他有用的方法：

print("The password is %s" % line)
print(("The password is %s") % (line))

Answer 2

这一行是无效的python3语法:(编辑：它是一个有效的语法！但不是你想要的:)）

print ("The password is %s") % (line);

请改用：

print ("The password is %s" % line)

另外，根据错误消息，行可能是None。

对SHA1哈希的字典攻击

2 个答案: