Question

我有这个SQL查询：

SELECT 
    DENSE_RANK() OVER (ORDER BY s.rows DESC) AS Ranks,
    Territory, TM_Name,
    COALESCE(g.rows, 0) AS RXCount, 
    COALESCE(s.rows, 0) AS DelCounts,
    COALESCE(nd.rows, 0) AS NotDeliveredCount,
    COALESCE(trgt.rows, 0) AS Target,
    e.TM_Emp_Id
FROM 
    tblEmployee e
LEFT JOIN
    (SELECT EmpCode, SUM(RxGenerate) AS rows 
     FROM tbl_RX 
     GROUP BY EmpCode) g ON g.EmpCode = e.TM_Emp_Id
LEFT JOIN
    (SELECT EmpCode, SUM(MedToPCount) AS rows 
     FROM tbl_MedicinToPatient 
     WHERE Status = 'Delivered' 
     GROUP BY EmpCode) s ON s.EmpCode = e.TM_Emp_Id
LEFT JOIN
    (SELECT EmpCode, COUNT(*) AS rows 
     FROM tbl_MedicinToPatient 
     WHERE Status != 'Delivered' 
     GROUP BY EmpCode) nd ON nd.EmpCode = e.TM_Emp_Id
LEFT JOIN
    (SELECT 
         EmpCode, CurrentTarget AS rows,   
         CreatedDate, RankOrder, T.PreviousTarget 
     FROM
         (SELECT
              EmpCode, CurrentTarget, CreatedDate,PreviousTarget,
              RANK() OVER (PARTITION BY EmpCode ORDER BY CreatedDate DESC) RankOrder
          FROM
              tbl_Target) T 
     WHERE 
         RankOrder = 1) trgt ON trgt.EmpCode = e.TM_Emp_Id

返回所需的输出。这是为每个用户计算完美排名。但是当我在查询结尾添加where条件时，例如：

e.TM_Emp_Id = 101

它显示等级1.对于每个用户，我得到相同的结果（即等级1）。但我想显示原始排名。我该如何实现这一目标？提前谢谢！

Answer 1

您至少有3个简单的选择。

将整个查询封装到子查询中，使其看起来像
```
select * 
from (current code) 
where TM_Emp_ID = 101
```

与上述相同，只是将其作为CTE：

WITH MY_QUERY AS 
(current code) 
SELECT * 
FROM MY_QUERY 
WHERE TM_EMP_ID = 101

与上述2相同，但使用临时表

Answer 2

您必须对所有用户进行排名才能了解特定用户的排名。因此，请从您的查询中选择：

select *
from ( your query here ) q
where tm_emp_id = 101;

排名显示所有用户罚款。但是如何显示一个用户的排名？

2 个答案: