我正在我的网站上显示一个带有AJAX的表格。我编写了一个JQuery代码,用于在通过AJAX发送表时对其进行排序,并单击<th>
- 标记。 (我不想使用插件。不,真的,我不想使用插件!)
这是我的代码:
PHP(index.php):
<form action="query.php" method="get">
<input type="search" name="query" autofocus="true" autocomplete="off" list="products">
<datalist id="products">
<?php
$sql = "SELECT * FROM products;";
$result = mysqli_query($con, $sql);
while ($product = mysqli_fetch_array($result)) {
echo "<option value=\"" . $product["productname"] . "\">" . $product["price"] . " $</option>";
}
?>
</datalist>
<button type="submit">Search</button>
</form>
<div class="result" align="center"></div>
PHP(query.php):
<?php
include_once "connection.php";
$query = trim($_GET["query"]);
$query = mysqli_real_escape_string($con, $query);
$sql = "SELECT * FROM products WHERE productname LIKE '%$query%' ORDER BY productname;";
$result = mysqli_query($con, $sql);
$result_no = mysqli_num_rows($result);
if ($result_no > 0) {
echo "<table>";
echo "<thead>";
echo "<tr>";
echo "<th>Product</th>";
echo "<th>Price</th>";
echo "<th>Quantity</th>";
echo "</tr>";
echo "</thead>";
echo "<tbody>";
while ($product = mysqli_fetch_array($result)) {
echo "<tr class=\"table\"><td align=\"left\">" . $product["productname"] . "</td><td align=\"right\">" . $product["price"] . " $</td><td align=\"right\">" . $product["quantity"] . "</td></tr>";
}
echo "</tbody>";
echo "<tfoot>";
if ($result_no == 1) {
echo "<tr><td colspan=\"3\" align=\"center\">" . $result_no . " product found." . "</td></tr>";
} else {
echo "<tr><td colspan=\"3\" align=\"center\">" . $result_no . " product found." . "</td></tr>";
}
echo "</tfoot>";
echo "</table>";
} elseif ($result_no <= 0) {
echo "<p>No products found.</p>";
}
mysqli_close($con);
?>
JQuery的:
$(document).ready(function() {
$("form").on("submit", function(event) {
event.preventDefault();
var form = $(this);
$.ajax({
type: this.method,
url: this.action,
data: form.serialize(),
cache: false,
success: function(data) {
$("div.result").html(data);
$("th").on("click", function() {
var column = $(this).index();
var tbody = $("tbody");
var rows = tbody.find("tr");
var dir = $(this).data("dir") || -1;
dir *= -1;
rows.sort(function(a, b) {
var aVal = $($(a).find("td")[column]).text().toLowerCase();
var bVal = $($(b).find("td")[column]).text().toLowerCase();
return aVal > bVal ? 1 * dir : aVal < bVal ? -1 * dir : 0;
});
$(this).data("dir", dir);
tbody.empty();
$(rows).appendTo(tbody);
});
}
});
});
});
connection.php用于连接我的数据库。我使用MySQL和PHPMyAdmin。我的表格是登录数据的“用户”和商店产品的“产品”。
我的问题:表格的第一行总是在错误的地方排序。
答案 0 :(得分:1)
使用内置的javascript sort功能。
js
以将排序后的方向存储在标题单元格中。compare
函数(请参阅链接的排序文档)。tbody
。编辑:更改了HTML,添加了功能以启用数字排序,而不仅仅是按字母顺序排序。 请注意number
类和排序函数中的新if
$("th").on("click", function() {
var column = $(this).index();
var numeric = $(this).hasClass("number"); //this class has been sprinkled to identify numeric sort.
var bdy = $(this).closest("table").find("tbody");
var rows = bdy.find("tr");
var dir = $(this).data("dir") || -1; //default direction is desc
dir *= -1; //reverse the stored direction
rows.sort(function(a, b) {
var aVal = $($(a).find("td")[column]).text().toLowerCase(); //get the text from one row
var bVal = $($(b).find("td")[column]).text().toLowerCase(); //get the text from row 2
if (numeric) { //added to handle numeric columns
aVal = parseFloat(aVal);
bVal = parseFloat(bVal);
}
return aVal > bVal ? 1 * dir : aVal < bVal ? -1 * dir : 0; // note the dir value to change direction
}); //sort the rows by the column content
bdy.empty(); //empty the body
$(rows).appendTo(bdy); //put the rows back
$(this).data("dir", dir); //log the direction
});
&#13;
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<table class="table">
<thead>
<tr class="table">
<th class="table">Product</th>
<th class="table number">Price</th>
<th class="table number">Quantity</th>
</tr>
</thead>
<tbody>
<tr class="table">
<td align="left" class="table">Chainsaw</td>
<td align="right" class="table">60.00 $</td>
<td align="right" class="table">1</td>
</tr>
<tr class="table">
<td align="left" class="table">Hammer</td>
<td align="right" class="table">24.99 $</td>
<td align="right" class="table">2</td>
</tr>
<tr class="table">
<td align="left" class="table">Nails (25 per Box)</td>
<td align="right" class="table">9.99 $</td>
<td align="right" class="table">21</td>
</tr>
<tr class="table">
<td align="left" class="table">Screwdriver</td>
<td align="right" class="table">29.99 $</td>
<td align="right" class="table">2</td>
</tr>
<tr class="table">
<td align="left" class="table">Screws (25 per Box)</td>
<td align="right" class="table">15.00 $</td>
<td align="right" class="table">26</td>
</tr>
</tbody>
<tfoot>
<tr class="table">
<td colspan="3" align="center" class="table">5 products found.</td>
</tr>
</tfoot>
</table>
&#13;
答案 1 :(得分:0)
@FelixRewer,请包含一个示例呈现表,您的问题已使用PHP更新。我相信PHP不是你的问题,而是另一端的HTML。
是的,也许你是对的。所以这里是一个代码片段,其中包含query.php和JQuery tablesorter的输出(我还添加了我的样式,我不认为它是相关的,但如果是,那么它就是。):
$("th").on("click", function() {
var column = $(this).index();
var table = $("table");
var tbody = table.find("tbody");
var rows = tbody.find("tr");
var dir = $(this).data("dir") || -1;
dir *= -1;
rows.sort(function(a, b) {
var aVal = $($(a).find("td")[column]).text().toLowerCase().trim();
var bVal = $($(b).find("td")[column]).text().toLowerCase().trim();
return aVal > bVal ? 1 * dir : aVal < bVal ? -1 * dir : 0;
});
$(this).data("dir", dir);
tbody.empty();
$(rows).appendTo(table);
});
&#13;
.table {
margin: 3vmax;
border: 1px solid #000000;
border-collapse: collapse;
color: #000000;
}
&#13;
<script src="https://ajax.googleapis.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<table class="table">
<thead>
<tr class="table">
<th class="table">Product</th>
<th class="table">Price</th>
<th class="table">Quantity</th>
</tr>
</thead>
<tbody>
<tr class="table">
<td align="left" class="table">Chainsaw</td>
<td align="right" class="table">60.00 $</td>
<td align="right" class="table">1</td>
</tr>
<tr class="table">
<td align="left" class="table">Hammer</td>
<td align="right" class="table">24.99 $</td>
<td align="right" class="table">2</td>
</tr>
<tr class="table">
<td align="left" class="table">Nails (25 per Box)</td>
<td align="right" class="table">9.99 $</td>
<td align="right" class="table">21</td>
</tr>
<tr class="table">
<td align="left" class="table">Screwdriver</td>
<td align="right" class="table">29.99 $</td>
<td align="right" class="table">2</td>
</tr>
<tr class="table">
<td align="left" class="table">Screws (25 per Box)</td>
<td align="right" class="table">15.00 $</td>
<td align="right" class="table">26</td>
</tr>
</tbody>
<tfoot>
<tr class="table">
<td colspan="3" align="center" class="table">5 products found.</td>
</tr>
</tfoot>
</table>
&#13;
是的,我在这里遇到同样的问题。我已经用我的代码测试了很多,我想可能第一行被排序在错误的位置,因为<tfoot>
,但这只是一个假设。
答案 2 :(得分:0)
此主题已关闭。这是我要找的代码:
$(document).ready(function() {
$("th").on("click", function() {
var column = $(this).index();
var table = $("table");
var tbody = table.find("tbody");
var rows = tbody.find("tr");
var dir = $(this).data("dir") || -1;
dir *= -1;
$(this).siblings().data("dir", -1);
rows.sort(function(a, b) {
var aVal = $($(a).find("td")[column]).html().toLowerCase().trim();
var bVal = $($(b).find("td")[column]).html().toLowerCase().trim();
if ($.isNumeric(aVal.charAt()) && $.isNumeric(bVal.charAt())) {
aVal = parseFloat(aVal);
bVal = parseFloat(bVal);
}
return aVal > bVal ? 1 * dir : aVal < bVal ? -1 * dir : 0;
});
$(this).data("dir", dir);
tbody.empty();
$(rows).appendTo(table);
});
});
&#13;
h1 {
color: #cc1100;
}
table {
width: 100%;
}
table,
tr,
td {
border: 1px solid #000000;
border-collapse: collapse;
}
tfoot,
thead {
text-align: center;
background-color: #cccccc;
}
th:hover {
cursor: pointer;
}
&#13;
<script src="https://ajax.googleapis.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<table>
<caption>
<h1>Tablesorter</h1>
</caption>
<thead>
<tr>
<th>Month</th>
<th>Savings</th>
</tr>
</thead>
<tbody>
<tr>
<td>January</td>
<td>$150</td>
</tr>
<tr>
<td>February</td>
<td>$160</td>
</tr>
<tr>
<td>March</td>
<td>$240</td>
</tr>
<tr>
<td>April</td>
<td>$160</td>
</tr>
</tbody>
<tfoot>
<tr>
<td colspan="2">Sum: $710</td>
</tr>
</tfoot>
</table>
&#13;
亲切的问候, Felix Rewer。