Xamarin Android应用程序使用线程崩溃

Question

我正试图通过Xamarin来掌握Android上的线程系统。

我想使用一个线程在后台执行一些代码，然后根据ui thread / fragment中该代码的返回值做出决定。

目前我是这样实现的：

DataRecordingFragment.cs

public override View OnCreateView(LayoutInflater inflater, ViewGroup container, Bundle savedInstanceState)
{
View v = inflater.Inflate(Resource.Layout.DataListFragment, container, false);

     Activity.Title = "My Data List";

     ListView lv = (ListView)v.FindViewById(Resource.Id.dataListView);

     lv.Adapter = new DataListItemAdapter(this.Activity, _dataList);
     lv.ItemClick += (object sender, AdapterView.ItemClickEventArgs e) => {
        var listView = sender as ListView;
             var dataItem = _dataList[e.Position];

             OptionsPopup(path, dataItem.Filename, listView, v.Context);
        };

        return v;
}

private void OptionsPopup(string path, string dataname, ListView lv, Android.Content.Context c)
    {
        var builder = new AlertDialog.Builder(this.Activity);

        builder.SetPositiveButton("Open", (sendere, args) =>
        {
    // open data file using intent
        })
        .SetNeutralButton("Delete", (senderee, args) 
   {
            // delete data file.
        })
        .SetTitle(dataname)
        .Show();
}

DataListingFragment.cs

lv.ItemClick += (object sender, AdapterView.ItemClickEventArgs e) => {
var listView = sender as ListView;
     var dataItem = _dataList[e.Position];

     OptionsPopup(path, dataItem.Filename, listView, v.Context);
};

单击列表视图项时应用程序崩溃：

<data-view [records]="records"
    (sendCache)="onValuesReceived($event, type = 'location')"
    (sendOrigFile)="onValuesReceived($event, type = 'origFile')"
    (sendStart)="onValuesReceived($event, type = 'start')"
    (sendEnd)="onValuesReceived($event, type = 'end')">
</data-view>

有什么想法吗？感谢。