Question

如果我在服务中有两个boolean方法，我怎样才能确保onSuccess方法处理返回boolean的正确方法？

例如，在onSuccess方法中我说：

if (result instanceof Boolean) {};

有没有办法可以区分返回布尔值的服务方法？否则，我无法保证在我的onSuccess方法中执行正确的代码，就好像结果是boolean，如果调用了我的两个boolean服务方法中的任何一个，它将会执行。

以下是我遇到的问题的一个例子：

private class DefaultCallback implements AsyncCallback
        {
        @Override
        public void onFailure(Throwable caught)
            {
            mainGUI.getServerResponseLabel().setStyleName("serverResponseLabelError");
            mainGUI.getServerResponseLabel().setHTML("An error occurred while "
                    + "attempting to contact the server. Please check your network " + "connection and try again.");
            }

        @Override
        public void onSuccess(Object result)
            {
            if (result instanceof Boolean)
                { 
                //
                I have two methods that return a boolean here, 
                so this block will execute no matter which one is called;
                for one method I want to display a GUI windows saying "Upload complete",          
                and for another, create an excel spreadsheet. But the boolean value of one method won't be relevant to the other

Answer 1

有很多灰色区域，但请耐心等待：在SomethingRPCService.java中

boolean isA();
boolean isB();

在SomethingRPCServiceAsync.java中

void isA(AsyncCallback<Boolean> callback);
void isB(AsyncCallback<Boolean> callback);

在您的活动中

somethingService.isA(new AsyncCallback<Boolean>() {
        @Override
        public void onSuccessImpl(final Boolean response) {
            //will be executed on success of THIS call
        }
        @Override
        public void onFailure(final Throwable caught) {
            // not relevant here
        }
});

somethingService.isB(new AsyncCallback<Boolean>() {
        @Override
        public void onSuccessImpl(final Boolean response) {
            //will be executed on success of THIS call
        }
        @Override
        public void onFailure(final Throwable caught) {
            // not relevant here
        }
});

你可以（必须？）实际输入你的回报

编辑：用你的例子，我可以看到更好一点;你的回调不应该是相同的，你应该覆盖它，所以代码不一样，因为它不是

在GWT异步回调中，如何在onSuccess中处理相同的返回类型？

1 个答案: