Python绘制网格函数

Question

我一直觉得画这样的网格有点困难..

我需要一些帮助来获得一个特定的功能，可以为我绘制任何给定的数字网格

def grid(f, l):
print("{:10}".format("---+---" * f))
print("|{:12}|".format(" " * l))
print("|{:12}|".format(" " * l))
print("|{:12}|".format(" " * l))
print("{:10}".format("---+---" * f))

Answer 1

那样的东西？

def grid(row, col):
  """version with string concatenation"""
  sep = '\n' + '+---'*col + '+\n'
  return sep + ('|   '*col + '|' + sep)*row

print(grid(3,7))

结果：

+---+---+---+---+---+---+---+
|   |   |   |   |   |   |   |
+---+---+---+---+---+---+---+
|   |   |   |   |   |   |   |
+---+---+---+---+---+---+---+
|   |   |   |   |   |   |   |
+---+---+---+---+---+---+---+

尽管使用列表理解与join

结合使用可能更有效

Answer 2

{{1}}

Answer 3

n=11
a=('+')*1 + (int(n/2)-1)*'-' + ('+')*1 + (int(n/2)-1)*'-' + ('+')*1
print(a)
for i in range(0,4):
    b=('|')*1 + (int(n/2)-1)*' ' + ('|')*1 + (int(n/2)-1)*' ' + ('|')*1
    print(b)
print(a)
for i in range(0,4):
    b=('|')*1 + (int(n/2)-1)*' ' + ('|')*1 + (int(n/2)-1)*' ' + ('|')*1
    print(b)    
print(a)