Question

这是mytable：

id | state   | orderid | name  | date
1  | Hold    | 121212  | Mike  | 2018-04-11
2  | Closed  | 121213  | Homer | 2018-04-12
3  | Open    | 121214  | Mike  | 2018-04-13
4  | Hold    | 121215  | Bart  | 2018-04-14
5  | Open    | 121216  | Lisa  | 2018-04-15
6  | Closed  | 121217  | Bart  | 2018-04-16
7  | Closed  | 121218  | Homer | 2018-04-17

我试图通过州（开放，保持，关闭），然后是日期（ASC），如果状态是＆＃34;关闭＆＃34;，然后是日期（DESC）。所以这样的结果。

id | state   | orderid | name  | date
3  | Open    | 121214  | Mike  | 2018-04-13
5  | Open    | 121216  | Lisa  | 2018-04-15
1  | Hold    | 121212  | Mike  | 2018-04-11
4  | Hold    | 121215  | Bart  | 2018-04-14
7  | Closed  | 121218  | Homer | 2018-04-17
6  | Closed  | 121217  | Bart  | 2018-04-16
2  | Closed  | 121213  | Homer | 2018-04-12

这是我现在的查询：

SELECT * FROM mytable ORDER BY FIELD(state,'Open','Hold','Closed') ASC, o_date DESC

尝试添加此处给出的示例：Can you add an if statement in ORDER BY? 但我没有得到我想要的结果。

有什么想法吗？

Answer 1

试试这个..

SELECT * FROM mytable 
ORDER BY FIELD(state,'Open','Hold','Closed') ASC, 
CASE WHEN state = 'Closed' THEN date END DESC,
date ASC

Mysql：根据多个列值重新排序结果，然后约会

1 个答案: