Question

我有一个函数，如下所示，看似合乎逻辑，但在运行时返回UNDEFINED。

程序应该返回下面的地址字符串，但代码没有以正确的顺序运行。任何人都可以就如何改进计划流程提供反馈意见吗？

function getAddress(lat, lon){

  apiKey = "API-KEY";
  geocodeAddress = "https://maps.googleapis.com/maps/api/geocode/json?latlng=" + lat + "," + lon + "&key=" + apiKey;

  const request = require('request-promise')
  request(geocodeAddress).then(res => {
  res = JSON.parse(res)
  //res.results[0].formatted_address = "12345 White House, Washington, DC 12345 USA"

    //Get rid of leading numbers/whitespace in address, only show street name
    newAddress = res.results[0].formatted_address.replace(/^\d+\s*/, '');

    //Get rid of Zip code and Country 
    newAddress = newAddress.split(',', 3).join(',').replace(/[0-9]/g, '').trim()

    //newAddress- Returns: "White House, Washington, DC"
    console.log(newAddress)


  }).then((newAddress)=> {

    //returns undefined
    return newAddress
  })
}

//Random 711
lat = 28.4177591;
lon = -81.5985051;

console.log("This returns undefined: ", getAddress(lat, lon))
var example2 = getAddress(lat, lon)
console.log("This also returns undefined: ", example2)

Answer 1

你在函数中做错了2件事：

request(geocodeAddress).then(res => {
//should be:
return request(geocodeAddress).then(res => {

console.log(newAddress)
//should be:
console.log(newAddress);return newAddress

当您调用该函数时，您将获得一个承诺，如果它在异步函数中使用，您可以使用等待或只使用promise.then方法：

lat = 28.4177591;
lon = -81.5985051;
getAddress(lat, lon)
.then(
  result=>console.log("This IS NOT undefined: ",result ),
  error=>console.warn("something went wrong:",error)
)

Javascript返回语句未执行 - 功能流程

1 个答案: