从列表中删除与条件匹配的第一个匹配项

Question

假设我有一个字符串列表：

first item
second item
# first commented item
third item
# second commented item

如何从列表中删除以#开头的第一个项目？

预期结果：

first item
second item
third item
# second commented item

Answer 1

>>> items = ["First", "Second", "# First", "Third", "# Second"]
>>> for e in items:
...     if e.startswith('#'):
...             items.remove(e)
...             break
... 
>>> items
['First', 'Second', 'Third', '# Second']

Answer 2

items = ["First", "Second", "# First", "Third", "# Second"]
for i in xrange(len(items)):
    if items[i][0] == '#':
        items.pop(i)
        break
print items