Question

我是IOS的新手所以这个问题可能适用于新手。我确切地知道我想做什么，但问题是如何做到这一点。我有字典的JSON数据，如

{
    "restaurants": [
        {
            "id": 1,
            "restaurantName": "Chuks",
            "restaurantPicture": "restaurantImages/benards.jpg",
            "status": "Working",
            "workingDays": "Tuesday to Sunday",
            "workingHours": "3pm to 10pm"
        },
        {
            "id": 3,
            "restaurantName": "Chuks",
            "restaurantPicture": "restaurantImages/benards.jpg",
            "status": "Working",
            "workingDays": "Tuesday to Sunday",
            "workingHours": "3pm to 10pm"
        },
        {
            "id": 4,
            "restaurantName": "Chuks",
            "restaurantPicture": "restaurantImages/benards.jpg",
            "status": "Working",
            "workingDays": "Tuesday to Sunday",
            "workingHours": "3pm to 10pm"
        },
        {
            "id": 5,
            "restaurantName": "Chuks",
            "restaurantPicture": "restaurantImages/benards.jpg",
            "status": "Working",
            "workingDays": "Tuesday to Sunday",
            "workingHours": "3pm to 10pm"
        },
        {
            "id": 6,
            "restaurantName": "Chuks",
            "restaurantPicture": "restaurantImages/benards.jpg",
            "status": "Working",
            "workingDays": "Tuesday to Sunday",
            "workingHours": "3pm to 10pm"
        }
    ]
}

我正试图用这段代码访问字典中的数组

override func viewDidLoad() {
    super.viewDidLoad()

    Alamofire.request(URL_GET_DATA).responseJSON { response in

        if let json = response.result.value {

            let RestaurantArray : NSArray = json as! NSArray

            for i in 0..<RestaurantArray.count{

                self.restaurant.append(Restaurant(
                    restaurantPicture: (RestaurantArray[i] as AnyObject).value(forKey: "restaurantPicture") as? String,
                    restaurantName: (RestaurantArray[i] as AnyObject).value(forKey: "restaurantName") as? String,
                    status: (RestaurantArray[i] as AnyObject).value(forKey: "status") as? String
                ))

            }

            self.tableViewRestaurants.reloadData()
        }

    }
    self.tableViewRestaurants.reloadData()
}

我收到此错误

Could not cast value of type '__NSSingleEntryDictionaryI' (0x1032e6e98) to 'NSArray' (0x1032e7f28).
2018-04-16 11:58:29.020876+0000 restaurant[6262:210307] Could not cast value of type '__NSSingleEntryDictionaryI' (0x1032e6e98) to 'NSArray' (0x1032e7f28).

我知道通过访问字典中的数组我想做什么，但问题是如何去做。当我准备好学习时，欢迎所有的帮助和批评。或者有没有办法在餐馆词典中尝试从数据库中获取数据而不使用它。谢谢大家

Answer 1

redis-cli: scan 0 MATCH my:key
redis-cli: 1) 18
redis-cli: 2) my:key
redis-cli: type my:key
redis-cli: list

Answer 2

无法转换类型＆＃39; __ NSSingleEntryDictionaryI＆＃39;的值（0x1032e6e98）到NSArray＆＃39; （0x1032e7f28）

明确表明//As per above response override func viewDidLoad() { super.viewDidLoad() Alamofire.request(URL_GET_DATA).responseJSON { response in if let json = response.result.value as! NSDictionary { let restaurantsArray = json["restaurants"] as! NSArray for dict in restaurantsArray { let ID = (dict as! NSDictionary).value(forKey: "id") as? Int //You can get more data like above } self.tableViewRestaurants.reloadData() } } }是字典，而不是数组。

<强>供参考：

字典由response.result.value表示，数组由{ }表示在JSON中。

更新您的代码，如下所示：

[ ]

Answer 3

你可以尝试这个：

        var arrExtractedData:NSMutableArray = NSMutableArray()

    if let jsonResponse = response.result.value as? [String: Any]{
        let arrRestaurants = json["restaurants"] as? [[String: Any]]

        for data in arrRestaurants {
            let tempDic:NSMutableDictionary = NSMutableDictionary()

            let id = dict["id"]
            tempDic.setValue(id, forKey: "id")
            let restaurantName = dict["restaurantName"]
            tempDic.setValue(restaurantName, forKey: "restaurantName")
            let restaurantPicture = dict["restaurantPicture"]
            tempDic.setValue(restaurantPicture, forKey: "restaurantPicture")
            let status = dict["status"]
            tempDic.setValue(status, forKey: "status")
            let workingDays = dict["workingDays"]
            tempDic.setValue(workingDays, forKey: "workingDays")
            let workingHours = dict["workingHours"]
            tempDic.setValue(workingHours, forKey: "workingHours")
            arrExtractedData.add(tempDic)
        }
    }

    print(arrExtractedData) //Extracted Data

Answer 4

您应该使用Codable协议。它确实使事情变得更容易。

看看，给出这个数据

let data = """
{
"restaurants": [
    {
        "id": 1,
        "restaurantName": "Chuks",
        "restaurantPicture": "restaurantImages/benards.jpg",
        "status": "Working",
        "workingDays": "Tuesday to Sunday",
        "workingHours": "3pm to 10pm"
    },
    {
        "id": 3,
        "restaurantName": "Chuks",
        "restaurantPicture": "restaurantImages/benards.jpg",
        "status": "Working",
        "workingDays": "Tuesday to Sunday",
        "workingHours": "3pm to 10pm"
    },
    {
        "id": 4,
        "restaurantName": "Chuks",
        "restaurantPicture": "restaurantImages/benards.jpg",
        "status": "Working",
        "workingDays": "Tuesday to Sunday",
        "workingHours": "3pm to 10pm"
    },
    {
        "id": 5,
        "restaurantName": "Chuks",
        "restaurantPicture": "restaurantImages/benards.jpg",
        "status": "Working",
        "workingDays": "Tuesday to Sunday",
        "workingHours": "3pm to 10pm"
    },
    {
        "id": 6,
        "restaurantName": "Chuks",
        "restaurantPicture": "restaurantImages/benards.jpg",
        "status": "Working",
        "workingDays": "Tuesday to Sunday",
        "workingHours": "3pm to 10pm"
    }
    ]
}
""".data(using: .utf8)!

这个结构

struct Response: Codable {
    let restaurants: [Restaurant]

    struct Restaurant: Codable {
        let id: Int
        let restaurantName: String
        let restaurantPicture: String
        let status: String
        let workingDays: String
        let workingHours: String
    }
}

您可以轻松获取Restaurant(s)的数组。

let restaurants = try? JSONDecoder().decode(Response.self, from: data).restaurants

访问字典中的数组

4 个答案: