我有这个：
SELECT put_id，ut_id，cm_tx，da，un FROM TA
ut_id | put_id | cm_tx | da | un
------|---------|--------------------------|------------|--------
21 | 21 | was good | 1523190974 | Jonah
22 | 21 | thx | 1523197793 | Sara
23 | 23 | that was good post | 1523201196 | Tom
24 | 24 | not good | 1523208390 | Lucas
25 | 24 | not good?? | 1523718726 | Stephen
26 | 24 | why u said not good? | 1523718805 | Stephen
27 | 24 | tell me why u said? | 1523718886 | Stephen
我想要的是什么：
ut_id | put_id | cm_tx | da | un
------|---------|--------------------------|------------|--------
21 | 21 | was good | 1523190974 | Jonah
22 | 21 | thx | 1523197793 | Sara
23 | 23 | that was good post | 1523201196 | Tom
24 | 24 | not good | 1523208390 | Lucas
27 | 24 | tell me why u said? | 1523718886 | Stephen
26 | 24 | why u said not good? | 1523718805 | Stephen
25 | 24 | not good?? | 1523718726 | Stephen
（事实上，我想排序唯一的＆＃34; ut_id！= put_id＆＃34;）ORDER BY da AND put_id
提前致谢
答案 0 :(得分：2)
正如我从你想要的输出中理解的那样，你想要按put_id排序，然后按ut_id = put_id排序，然后按日期降序排序。你可以通过以下方式实现这一目标：
SELECT put_id,ut_id,cm_tx,date,un FROM TA ORDER BY put_id ASC, IF(ut_id = put_id, 0, 1) ASC, date DESC
输出：
put_id ut_id cm_tx date un
21 21 was good 1523190974 Jonah
21 22 thx 1523197793 Sara
23 23 that was good post 1523201196 Tom
24 24 not good 1523208390 Lucas
24 27 tell me why u said? 1523718886 Stephen
24 26 why u said not good? 1523718805 Stephen
24 25 not good?? 1523718726 Stephen