Question

现在我想在循环中获取数组数据。

{
"rajaongkir": {
    "query": {
      "origin": "23",
      "destination": "152",
      "weight": 1500,
      "courier": "all"
    },
    "status": {
      "code": 200,
      "description": "OK"
    },
    "origin_details": {
      "city_id": "23",
      "province_id": "9",
      "province": "Jawa Barat",
      "type": "Kota",
      "city_name": "Bandung",
      "postal_code": "40000"
    },
    "destination_details": {
      "city_id": "152",
      "province_id": "6",
      "province": "DKI Jakarta",
      "type": "Kota",
      "city_name": "Jakarta Pusat",
      "postal_code": "10000"
    },
    "results": [
      {
        "code": "pos",
        "name": "POS Indonesia (POS)",
        "costs": [
          {
            "service": "Surat Kilat Khusus",
            "description": "Surat Kilat Khusus",
            "cost": [
              {
                "value": 16500,
                "etd": "2-4",
                "note": ""
              }
            ]
          },
          {
            "service": "Express Next Day",
            "description": "Express Next Day",
            "cost": [
              {
                "value": 22000,
                "etd": "1",
                "note": ""
              }
            ]
          }
        ]
      },
      {
        "code": "jne",
        "name": "Jalur Nugraha Ekakurir (JNE)",
        "costs": [
          {
            "service": "OKE",
            "description": "Ongkos Kirim Ekonomis",
            "cost": [
              {
                "value": 18000,
                "etd": "2-3",
                "note": ""
              }
            ]
          },
          {
            "service": "REG",
            "description": "Layanan Reguler",
            "cost": [
              {
                "value": 20000,
                "etd": "1-2",
                "note": ""
              }
            ]
          },
          {
            "service": "YES",
            "description": "Yakin Esok Sampai",
            "cost": [
              {
                "value": 30000,
                "etd": "1-1",
                "note": ""
              }
            ]
          }
        ]
      },
      {
        "code": "tiki",
        "name": "Citra Van Titipan Kilat (TIKI)",
        "costs": [
          {
            "service": "SDS",
            "description": "Same Day Service",
            "cost": [
              {
                "value": 135000,
                "etd": "",
                "note": ""
              }
            ]
          },
          {
            "service": "HDS",
            "description": "Holiday Delivery Service",
            "cost": [
              {
                "value": 49000,
                "etd": "",
                "note": ""
              }
            ]
          },
          {
            "service": "ONS",
            "description": "Over Night Service",
            "cost": [
              {
                "value": 26000,
                "etd": "",
                "note": ""
              }
            ]
          },
          {
            "service": "REG",
            "description": "Regular Service",
            "cost": [
              {
                "value": 17000,
                "etd": "",
                "note": ""
              }
            ]
          },
          {
            "service": "ECO",
            "description": "Economi Service",
            "cost": [
              {
                "value": 14000,
                "etd": "",
                "note": ""
              }
            ]
          }
        ]
      }
    ]
  }
}

我试图获取数组数据并将其附加到组合框。结果是数据显示全部为双/重复。

这是获取数组数据的JS：

$.ajax({
    type : 'POST',
    url : 'cek_ongkir.php',
    dataType: "JSON",
    data :  {'kab_id' : kab, 'kurir' : kurir, 'asal' : asal, 'berat' : berat},
    success: function (jsonStr) {
        $.each(jsonStr['rajaongkir']['results'], function(i,n)
        {
            var len = n['costs'].length;

            for(var i=0; i<len; i++)
            {
                cou = '<option value="'+n['costs'][0]['cost'][0]['value']+'">'+n['costs'][0]['description']+'</option>';
                cou = cou + '';
                $("#service").append(cou);
            }
        });

        $("#service").prop('disabled', false);
    }
});

我不知道我需要将[i]放在该循环上。

Answer 1

您需要i才能访问costs数组的每个对象。

<强>替换

cou = '<option value="'+n['costs'][0]['cost'][0]['value']+'">'+n['costs'][0]['description']+'</option>';

<强>与

cou = '<option value="'+n['costs'][i]['cost'][0]['value']+'">'+n['costs'][i]['description']+'</option>';

由于您在循环中使用n['costs'][0]因此它将始终返回costs数组的第一个对象，这就是您的选项重复的原因。要在循环内访问数组的每个对象，必须使用从数组的0到length-1的循环中获得的数组的索引。因此，您必须在代码中使用n['costs'][i]才能使其按预期工作。

获取数组数据循环并使用jQuery将其附加到组合框副本上

1 个答案: