Question

所以我需要专门使用struct tm来打印我的生日，这是我成功的。但是，我还需要使用strftime（）以不同的格式打印它。这就是我遇到问题的地方，因为strftime（）只识别指针参数。

#include <stdio.h>
#include <time.h>

int main(){

    struct tm str_bday;
    time_t time_bday;
    char buffer[15];

    str_bday.tm_year = 1994 - 1900 ;
    str_bday.tm_mon = 7 - 1;
    str_bday.tm_mday = 30;
    str_bday.tm_hour = 12;
    str_bday.tm_min = 53;
    time_bday = mktime(&str_bday);
    if(time_bday == (time_t)-1)
        fprintf(stdout,"error\n");
    else
        {
        fprintf(stdout,"My birthday in second is: %ld \n",time_bday);
        fprintf(stdout,"My birthday is: %s\n", ctime(&time_bday));//Wed July 22 12:53:00 1998
        strftime(buffer,15,"%d/%m/%Y",time_bday);
        fprintf(stdout,"My birthday in D/M/Y format is %s",buffer);
        }
    return 0;
}

错误是：

Error:  passing argument 4 of ‘strftime’ makes pointer from integer without a cast

    expected ‘const struct tm * restrict’ but argument is of type ‘time_t’

有人可以告诉我如何解决它吗？

编辑：将time_bday更改为＆amp; str_bday有效！但现在程序每次运行都会输出随机时间和日期。

编辑：在strftime（）之后使用put（缓冲区）而不是fprintf（），它完美地运行了。另外，将缓冲区[15]更改为缓冲区[30]，因为我有小时，分钟和秒。

Answer 1

通过查看strftime的原型，您可以看到您应该传递const struct tm*作为最后一个参数：

size_t strftime(char *s, size_t maxsize, const char *format, const struct tm *timeptr);

在您的情况下，&str_bday代替time_bday。

struct tm有两个你没有初始化的字段，因此会获取不确定的值，导致你看到的时间跳跃。在插入值之前，您可以使用struct tm str_bday = {0}将所有字段初始化为零。

Answer 2

mktime(&str_bday);在struct tm的计算中取决于time_t的各种成员¹。

首先将成员初始化为0是一种很好的做法。

// struct tm str_bday;
struct tm str_bday = { 0 };

OP的代码无法初始化某些成员，例如tm_sec，这肯定会导致错误的结果。

然而，初始化所有相关成员也很重要。 OP的代码不会分配tm_isdst和struct tm str_bday = { 0 }，这就像

str_bday.tm_isdst = 0; // Set time stamp to **standard** time.

问题在于OP's school，该日期的日光时间设置肯定是夏令时。

// add
str_bday.tm_isdst = -1; // Let mktime() determine DST setting
// or if one knowns it is daylight time.
str_bday.tm_isdst = 1; // Set time stamp to **daylight** time.
// or if one knowns it is standard time.
str_bday.tm_isdst = 0; // Set time stamp to **standard** time.

在ctime(&time_bday)

的打印中，错误应该很明显

// My birthday is: Sat Jul 30 13:53:00 1994
My birthday is: Sat Jul 30 12:53:00 1994

更正后的代码

#include <locale.h>
#include <time.h>
int main() {

  struct tm str_bday = { 0 };
  time_t time_bday;
  char buffer[15];

  str_bday.tm_year = 1994 - 1900;
  str_bday.tm_mon = 7 - 1;
  str_bday.tm_mday = 30;
  str_bday.tm_hour = 12;
  str_bday.tm_min = 53;
  str_bday.tm_isdst = -1;
  time_bday = mktime(&str_bday);

  strftime(buffer, sizeof buffer, "%d/%m/%Y", &str_bday);
  if (time_bday == (time_t) -1) {
    fprintf(stdout, "error\n");
  } else {
    // Do not assume `long`.  Better to cast to a wide type. 
    fprintf(stdout, "My birthday in second is: %lld \n", (long long) time_bday);
    fprintf(stdout, "My birthday is: %s", ctime(&time_bday));
    // strftime(buffer,15,"%d/%m/%Y",time_bday);
    strftime(buffer, sizeof buffer, "%d/%m/%Y", &str_bday);
    fprintf(stdout, "My birthday in D/M/Y format is %s\n", buffer);
  }
  return 0;
}

¹成员tm_wday和tm_yday不参与计算，但会更新。

使用struct tm打印特定日期和strftime

2 个答案: