Question

我在Python和sqlite中有一些代码，在执行和打印时会返回正确的数据。但是当我尝试将其传递给HTML时，它会从错误的表中检索数据并将其显示给HTML。例如，我执行以下python代码：

comments = c.execute('''SELECT * FROM comments''')
conn.commit    
for each in comments:
    print(each)
newsubs = c.execute('''SELECT * FROM submissions WHERE Signiture = signiture AND Client_ID = client_ID ORDER BY date DESC''')
conn.commit()
print("hello")
var = "hello,!"
return render_template('profile.html', comments = comments, newsubs = newsubs)

然后，我在评论和新闻栏中调用以下HTML代码来显示数据：

{% for y in newsubs %}
            <br>
                <div id="subcss">
            <legend><strong> {{ y[2] }} </strong> {{ y[4] }} <br><br></legend>
                {{ y[3] }} <br><br>
                <p id = "sig"><strong>Signiture:</strong> {{ y[5] }}</p>
                {{ y[1] }} <br><br>
            <div id="subcss">
            <form action="/comments" method="post">
                <textarea name="comment" rows="7" cols="76">Write a comment...</textarea><br>
                <input type="submit" value="Submit"><br><br><br>
            <button onclick="myFunction()">View Comments</button>
            <div id="comdiv">
                {% for z in comments %}
                    <strong>Date:</strong> {{ z[0] }} <br>
                    <strong>Comment:</strong> {{ z[1] }} <br><br>
                    {{ z[2] }}
                    <br>{ z[3] }} {{ z[4] }}
                <br>
                {% endfor %}
            </form><br>
            </div>
            {% endfor %}
    </div>
    </div>

问题是从这段代码输出到网页：

{% for z in comments %}
                    <strong>Date:</strong> {{ z[0] }} <br>
                    <strong>Comment:</strong> {{ z[1] }} <br><br>
                    {{ z[2] }}
                    <br>{ z[3] }} {{ z[4] }}
                <br>
                {% endfor %}

显示提交表中的数据，而不是评论表。任何帮助或任何事情都非常感谢。

jinja2从sqlite数据库返回错误的值

0 个答案: