Question

我通过使用数组在java中进行了赋值，这里有一些如何编写程序的指令。 我在第2步遇到的问题应该如何初始化数组以显示如下所示的输出（1 A B C D）。

为座位安排编写一个java程序。该计划应具有以下

1 /要求用户输入座位安排中的行数（完成）

2 /根据输入的行，使用数组和循环分配初始座位编号和显示如下：

     Example if you enter ----- > row = 3
     The display will be:
      1 A B C D
      2 A B C D
      3 A B C D

3 /要求用户选择他们想要的座位以及所选座位的指定“X”。（完成）将要求用户输入，直到给出哨兵值以停止进入。

4 /在指定的“X”

值后显示座位图案

 Example if the user choose ----- > 1A 2B 3D
    The display will be:
   1 X B C D
   2 A X C D
   3 A B C X

我编写了代码，但是在一个问题中，我遇到了2D数组的问题，我不知道如何初始化数组它是String还是char数组？

我的代码

import java.util.Scanner;

public class Test {

    public static void main(String[] args) {

        Scanner s = new Scanner(System.in);

        System.out.println("Enter how many row in seating arrangment: ");
        int rowNo = s.nextInt();

        String seating[][] = new String[rowNo][4];
        for (int i = 0; i < rowNo; i++) {
            for (int j = 0; j < 4; j++) {
                if (j == 0)
                    seating[i][j] = "A";
                else if (j == 1)
                    seating[i][j] = "B";
                else if (j == 2)
                    seating[i][j] = "C";
                else
                    seating[i][j] = "D";
            }
        }

        for (int i = 0; i < rowNo; i++) {
            System.out.println(i + 1);
            for (int j = 0; j < 4; j++) {
                System.out.println((j + 1) + "\t" + seating[i][j]);
            }
            System.out.println();
        }

        String askUser = "Y";
        while (askUser.equalsIgnoreCase("Y")) {
            System.out.println("Chose your Seat ");

            System.out.println("Enter the row  ");
            int row = s.nextInt();

            System.out.println("Enter the column  ");
            String col = s.nextLine();

            if (col.equals("A"))
                seating[row - 1][0] = "X";
            else if (col.equals("B"))
                seating[row - 1][1] = "X";
            else if (col.equals("C"))
                seating[row - 1][2] = "X";
            else
                seating[row - 1][3] = "X";

            System.out.println("Contnioe to choose seat [y -Yes | n-No] :");
            askUser = s.next();
        }

        System.out.println("Find Seating");
        for (int i = 0; i < rowNo; i++) {
            for (int j = 0; j < 4; j++) {
                System.out.println((j + 1) + "\t" + seating[i][j]);
            }
            System.out.println();
        }
    }
}

我的代码输出

     Enter how many row in seating arrangment: 

    3
    1
    1   A
    2   B
    3   C
    4   D

    2
    1   A
    2   B
    3   C
    4   D

  Chose your Seat 
  Enter the row  
   2
  Enter the column  
  A
  Contnioe to choose seat [y -Yes | n-No] :

 Find Seating
 1  A
 2  B
 3  C
 4  D

1   A
2   B
3   C
4   X

我的代码中出现了什么错误？ 教师提示：行号应存储在一维字符串数组中。应该为字符使用2D数组。

我正在寻求帮助。问候

但是如果我这样做那么2d数组是正确的吗？

 String seatRow[]= new String[rowNo];
 char [] col= {'A','B','C','D'};
//String[] col= {"a b c d "};
String s=Arrays.toString(col);
String SeatAval[][]= new String [rowNo][s.length()];

我对教师提供的提示设置字符串数组中的行感到困惑。和人物。

Answer 1

我已经编辑了您的代码并添加了注释，以便您知道出了什么问题。请阅读并理解。此外，您应该添加一些错误检查，以防用户提供错误的输入。这是更新的代码：

import java.util.Scanner;

public class Test {

    public static void main(String[] args) {

        Scanner s = new Scanner(System.in);

        System.out.println("Enter number of rows in seating arrangment: ");
        int rowNo = s.nextInt();

        String[][] seating = new String[rowNo][4];
        for (int i = 0; i < rowNo; i++) {
            for (int j = 0; j < 4; j++) {
                if (j == 0)
                    seating[i][j] = "A";
                else if (j == 1)
                    seating[i][j] = "B";
                else if (j == 2)
                    seating[i][j] = "C";
                else
                    seating[i][j] = "D";
            }
        }

        // Extracted your printing into a method
        printSeating(seating);

        String askUser = "Y";
        while (askUser.equalsIgnoreCase("Y")) {
            System.out.println("Chose your Seat ");

            System.out.println("Enter the row  ");
            int row = s.nextInt();
            // nextInt() only gets the int and doesn't consume the newline
            // so this consumes the newline
            s.nextLine();

            System.out.println("Enter the column  ");
            String col = s.nextLine();

            if (col.equals("A"))
                seating[row - 1][0] = "X";
            else if (col.equals("B"))
                seating[row - 1][1] = "X";
            else if (col.equals("C"))
                seating[row - 1][2] = "X";
            else
                seating[row - 1][3] = "X";

            System.out.println("Contnioe to choose seat [y -Yes | n-No] :");
            askUser = s.next();
        }

        System.out.println("Find Seating");
        // Extracted your printing into a method
        printSeating(seating);
    }


    private static void printSeating(String[][] seating) {
        for (int i = 0; i < seating.length; i++) {
            // Don't print a newline, since you want to continue printing on this line
            System.out.print(i + 1);
            for (int j = 0; j < seating[i].length; j++) {
                // Don't print a newline, since you want to continue printing on this line
                System.out.print(" " + seating[i][j]);
            }
            // now you print a newline
            System.out.println();
        }
    }
}

Java 2D Arrays string或char Seating managment

1 个答案: