Question

我正在使用以下代码来显示mysql数据。问题是在以HTML格式显示数据时，数据显示在一行中而不会被包装。

UseSqlServer

请帮我解释一下代码。

Answer 1

您缺少关闭<tr>标记，因此，您的所有数据都在同一行。

while($res = mysqli_fetch_array($result)) { 
    echo "<tr>";
    echo "<td>".$res['topic']."</td>";
    echo "<td>".$res['issue']."</td>";
    echo "<td>".$res['solution']."</td>";
    echo "<td><div align='center'><a href=\"edit.php?id=$res[id]\">Edit</a> | <a href=\"delete.php?id=$res[id]\" onClick=\"return confirm('Are you sure you want to delete?')\">Delete</a></td>";  
    echo "</tr>"; // << close <tr> tag     
}

Answer 2

使用<br>打破该行。

Answer 3

首先，您必须打印<table>才能创建表格

echo "<table>";
.
.
.
.
echo "</table>";

＆＃13;

without table tag<br>
<tr>
    <td>Peter</td>
    <td>Griffin</td>
  </tr>
  <tr>
    <td>Lois</td>
    <td>Griffin</td>
  </tr>
  <br>
with table taaag
<table>
 <tr>
    <td>Peter</td>
    <td>Griffin</td>
  </tr>
  <tr>
    <td>Lois</td>
    <td>Griffin</td>
  </tr>
</table>

＆＃13;

Answer 4

试试这个演示，为演示使用数组而不是表数据，

<?php
$data=array(array("id"=>1,"topic"=>"php","issue"=>"var 
error","solution"=>"declare 
first"),array("id"=>2,"topic"=>"asp","issue"=>"var error 
validatipn","solution"=>"validate js add")); 
?>
<table border="1">
    <thead>
    <tr><th>topic</th><th>issue</th><th>solution</th><th>Action</th></tr>
    </thead>
    <tbody>
<?php
 foreach($data as $res)
 { 
 echo "<tr>";
 echo "<td>".$res['topic']."</td>";
 echo "<td>".$res['issue']."</td>";
 echo "<td>".$res['solution']."</td>";
 echo "<td><div align='center'><a href=\"edit.php?id=$res[id]\">Edit</a> | 
 <a 
href=\"delete.php?id=$res[id]\" onClick=\"return confirm('Are you sure you 
want to delete?')\">Delete</a></td></tr>";       
 }
 ?>
 </tbody>
</table>

Php mysql在html中获取数组结果

4 个答案: