python 3.5中的zip函数，包含超过255个参数

Question

我在代码中有一个zip函数，给出了错误“SyntaxError：超过255个参数”

sentences_join = [' '.join(x) for x in zip(sentences[0::256], sentences[1::256], sentences[2::256], sentences[3::256], ..., sentences[255::256])]

如何将此函数压缩为少于255个参数？

Answer 1

尝试

sentences_join = [' '.join(x) for x in zip(*(sentences[n::256] for n in range(256)))]

Answer 2

apply函数的Pythonic方式可以将迭代变为参数：

sentences_join = [' '.join(x) for x in zip(*map(lambda i: sentences[i::256], range(256)))]