Question

我是Python的初学者。我的数据框df_all_data_0包含列time_in：

2018-01-13 13:17:29
2018-01-06 17:49:43
2018-01-18 09:44:37
2018-01-04 10:45:52
2018-01-11 12:58:31

我想分开日期（例如2018-01-13）和时间（13:17:29）。我尝试了什么：

pd.to_datetime(df_all_data_0['time_in']).
date_str = df_all_data_0.strptime('%Y-%m-%d')

但我有错误：

AttributeError                            Traceback (most recent call last)
<ipython-input-14-d662eee68034> in <module>()
      8 
      9 
---> 10 date_str = df_all_data_0.strptime('%Y-%m-%d')
     11 #print(type(date_str)) # <class 'str'>
     12 #print(date_str) # 2017-10-24

/anaconda/lib/python3.6/site-packages/pandas/core/generic.py in __getattr__(self, name)
   2968             if name in self._info_axis:
   2969                 return self[name]
-> 2970             return object.__getattribute__(self, name)
   2971 
   2972     def __setattr__(self, name, value):

AttributeError: 'DataFrame' object has no attribute 'strptime'

如何纠正？

Answer 1

一种方法是使用pd.Series.dt.time提取日期，时间设置为0，import pandas as pd from io import StringIO mystr = StringIO("""2018-01-13 13:17:29 2018-01-06 17:49:43 2018-01-18 09:44:37 2018-01-04 10:45:52 2018-01-11 12:58:31""") df = pd.read_csv(mystr, sep='|', header=None, names=['DateTime']) df['DateTime'] = pd.to_datetime(df['DateTime']) df['Date'], df['Time'] = df['DateTime'].dt.normalize(), df['DateTime'].dt.time print(df) # DateTime Date Time # 0 2018-01-13 13:17:29 2018-01-13 13:17:29 # 1 2018-01-06 17:49:43 2018-01-06 17:49:43 # 2 2018-01-18 09:44:37 2018-01-18 09:44:37 # 3 2018-01-04 10:45:52 2018-01-04 10:45:52 # 4 2018-01-11 12:58:31 2018-01-11 12:58:31提取时间：

Time

请注意，dtype列将包含print(df.dtypes) # DateTime datetime64[ns] # Date datetime64[ns] # Time object # dtype: object对象：

{{1}}

如何在DataFrame中分隔日期和时间

1 个答案: