Question

我有跟随dict并希望根据值列表从中获取密钥：

d = {
'Mot': [5250, 1085, 1085, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0],
'Dek': [0, 0, 0, 105, 0, 0, 0, 0, 0, 0, 0, 0, 0],
'Nas': [0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0],
'Ost': [0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0],
'Suk': [0, 0, 0, 0, 0, 0, 0, 3156, 1320, 450, 0, 0, 0],
'Tas': [0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 250, 0, 0],
'Sat': [0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 6551, 5000]
}
    dz = [[5250, 1085, 1085, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0],
[0, 0, 0, 105, 0, 0, 0, 0, 0, 0, 0, 0, 0]]

我试图采用get（）方法而没有任何成功（返回此错误：不可用类型：＆＃39; list＆＃39 ;;当我尝试使用numpy＆＃39; s数组而不是返回时，同样的情况发生了：unhashable类型：＆＃39; numpy.ndarray＆＃39;）：

tN= []
for index, element in enumerate(dz):
    tN.append(dict((v,k) for k,v in dict_res.items()).get(element))

有没有办法如何从字典中检索值？

Answer 1

您可以这样做：

d = {
'Mot': [5250, 1085, 1085, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0],
'Dek': [0, 0, 0, 105, 0, 0, 0, 0, 0, 0, 0, 0, 0],
'Nas': [0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0],
'Ost': [0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0],
'Suk': [0, 0, 0, 0, 0, 0, 0, 3156, 1320, 450, 0, 0, 0],
'Tas': [0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 250, 0, 0],
'Sat': [0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 6551, 5000]
}

dz = [[5250, 1085, 1085, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0],[0, 0, 0, 105, 0, 0, 0, 0, 0, 0, 0, 0, 0]]

keys = [key for elem in dz for key, value in d.items() if elem==value]
print(keys)

输出：

['Mot', 'Dek']

<强>更新

修改代码，以便获得正确的密钥顺序。如果：

dz = [[0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 6551, 5000],
    [5250, 1085, 1085, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0],
      [0, 0, 0, 105, 0, 0, 0, 0, 0, 0, 0, 0, 0]]

输出是：

['Sat', 'Mot', 'Dek']

Answer 2

Vasilis G.上面发布的解决方案很遗憾地重新排序了返回值，以便在以下情况下使用：

dz = [[0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 6551, 5000],
    [5250, 1085, 1085, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0],
      [0, 0, 0, 105, 0, 0, 0, 0, 0, 0, 0, 0, 0]]

输出：

['Mot', 'Dek', 'Sat']

对于需要知道列表中值的真实顺序的情况，这可能是更好的选择：

keys = []
for i in dz:
    keys.append(list(d.keys())[list(d.values()).index(i)])
#using list comprehension:
#keys = [list(d.keys())[list(d.values()).index(i)] for i in dz]

print(keys)

打印：

['Sat', 'Mot', 'Dek']

如何根据值列表的匹配从Python字典中检索值

2 个答案: