Question

我正在尝试写入对象内的变量，但我找不到如何做到这一点。

            Array
            (
                [0] => stdClass Object
                    (
                        [id] => 3
                        [rota_name] => Tea and coffee
                        [rota_owner_name] => 9
                        [rota_notes] => 
                        [rota_entry] => {"rota_entry0":{"person":"8","rota_assignment_date":"2018-04-01 20:17:48","rota_role":""},"rota_entry1":{"person":"7","rota_assignment_date":"2018-04-08 20:17:48","rota_role":""},"rota_entry2":{"person":"11","rota_assignment_date":"2018-04-15 20:17:48","rota_role":""},"rota_entry3":{"person":"7","rota_assignment_date":"2018-04-22 20:17:48","rota_role":""},"rota_entry4":{"person":"10","rota_assignment_date":"2018-04-29 20:17:48","rota_role":""},"rota_entry5":{"person":"3","rota_assignment_date":"2018-05-06 20:18:20","rota_role":""},"rota_entry6":{"person":"11","rota_assignment_date":"2018-05-13 20:18:23","rota_role":""}}
                        [rota_advance_email_days] => 
                        [rota_reminder_sent] => 
                    )

我想将8人改为9人

所以我认为我需要获得rota_entry（使用foreach），然后使用Json_decode获取一个数组，然后我的大脑现在会受伤:(我不知道如何将其重置为数据库再次。

我可以找到许多谈论简单的JSON解码或简单的数组解析，但没有什么可以帮助解决这个问题

Answer 1

此代码假设$ obj =您显示的数组中的第一个条目。

所以$ obj = Array [0]

$json = json_decode($obj->rota_entry);
$json->rota_entry0->person = 9;

$obj->rota_entry = json_encode($json);

此代码将rota_entry0 person 8更改为

Answer 2

// Your original array
$array = [
        0 => (object) [
        'id' => 3,
        'rota_name' => 'Tea and coffee',
        'rota_owner_name' => 9,
        'rota_notes' => '',
        'rota_entry' =>' {"rota_entry0":{"person":"8","rota_assignment_date":"2018-04-01 20:17:48","rota_role":""},"rota_entry1":{"person":"7","rota_assignment_date":"2018-04-08 20:17:48","rota_role":""},"rota_entry2":{"person":"11","rota_assignment_date":"2018-04-15 20:17:48","rota_role":""},"rota_entry3":{"person":"7","rota_assignment_date":"2018-04-22 20:17:48","rota_role":""},"rota_entry4":{"person":"10","rota_assignment_date":"2018-04-29 20:17:48","rota_role":""},"rota_entry5":{"person":"3","rota_assignment_date":"2018-05-06 20:18:20","rota_role":""},"rota_entry6":{"person":"11","rota_assignment_date":"2018-05-13 20:18:23","rota_role":""}}',
        'rota_advance_email_days' => '',
        'rota_reminder_sent' => '',
        ]
];

// Create an empty object to replace the rota_entry key in the array
$rotaEntry = (object) [];

// Iterate through the original rota_entry and replace "person"
foreach (json_decode($array[0]->rota_entry) as $key => $value) {
    // You can set whatever logic you want here
    // For example: if ($key == "rota_entry4") {$value->person = 4;}
    // I'm hardcoding "9"
    $value->person = 9;
    $rotaEntry->$key = $value;
}

// Assign the newly created (and modified) rotaEntry back to the original array
$array[0]->rota_entry = $rotaEntry;

Answer 3

试试这个：

$array = (array) $object;

foreach($array as &$value){
    $json = json_encode($value['rota_entry']);
    $json -> rota_entry0 -> person = 9;
    $value['rota_entry'] = json_encode($json);
}

$array = (object) $array;

祝你好运。

php对象和数组

3 个答案: