Question

我已经建立了地址模型，地址列表和创建地址。我的问题是创建视图不会将浏览器重定向到success_url。正确显示创建视图，提交后，新地址将添加到数据库，但地址不会更改。因此，用户认为它失败了，因此再次点击提交。直接更改浏览器IP地址将显示多次创建的地址。我创建了一个简单的项目并在其中重复此代码，浏览器会按预期重定向到列表视图。我也试过覆盖get_success_url（self）而没有任何改变。我已经改变了success_url，再没有改变。我知道这在开发的早期阶段起作用，但在最终测试中发现它已经破裂。

这是我的控制台输出，以初始地址列表视图开始。

[13/Apr/2018 12:42:57] "GET /accounts/my_address/ HTTP/1.1" 200 4853
[13/Apr/2018 12:43:01] "GET /accounts/create-address/ HTTP/1.1" 200 5715
[13/Apr/2018 12:43:11] "POST /accounts/create-address/ HTTP/1.1" 302 0
[13/Apr/2018 12:43:11] "GET /accounts/my_address/ HTTP/1.1" 200 5898

控制台日志说它正在做正确的事情，但浏览器地址栏是/ accounts / create-address /而不是/ accounts / my_address /

我的问题是我如何调试它来确定浏览器没有改变的原因，即

models.py

class Address(models.Model):
    """
    Allow an account to have multiple addresses for which one
    must be active. Shipments will be sent to the active address.
    """
    STREET_LENGTH = 128
    CITY_LENGTH = 64
    STATE_LENGTH = 32
    POSTAL_CODE_LENGTH = 10
    account = models.ForeignKey(Account, on_delete=models.CASCADE)
    active = models.BooleanField(help_text='Select the Active address')
    street = models.CharField(max_length=STREET_LENGTH)
    city = models.CharField(max_length=CITY_LENGTH)
    state = models.CharField(max_length=STATE_LENGTH)
    postal_code = models.CharField(max_length=POSTAL_CODE_LENGTH)

forms.py

class AddressForm(forms.ModelForm):
    model = Address
    street = forms.CharField(max_length=Address.STREET_LENGTH, label='Street:',
                         required=False, widget=forms.TextInput(
                             attrs={'class': 'form-control', 'autofocus': 'autofocus'}),)

     postal_code = forms.CharField(max_length=Address.POSTAL_CODE_LENGTH, label='Postal Code:',
                              required=False, widget=forms.TextInput(attrs={'class': 'form-control postal_code'}))

     city = forms.CharField(max_length=Address.CITY_LENGTH, label='City:',
                       required=False, widget=forms.TextInput(attrs={'class': 'form-control city'}))

     state = forms.CharField(max_length=Address.STATE_LENGTH, label='State:',
                        required=False, widget=forms.TextInput(attrs={'class': 'form-control state'}))

urls.py

urlpatterns = [
    path('my_address/', AddressListView.as_view(), name='my_address'),
    path('create-address/', AddressCreateView.as_view(), 
         name="create-address"),
]

views.url

class AddressListView(LoginRequiredMixin, ListView):
    model = Address
    def get_queryset(self):
        account = self.request.user
        addresses = Address.objects.filter(account=account).order_by('-active')
        return addresses

    def get_context_data(self, *, object_list=None, **kwargs):
        context = super(AddressListView, self).get_context_data(**kwargs)
        account = self.request.user
        context['account'] = account
        return context

class AddressCreateView(LoginRequiredMixin, SuccessMessageMixin, CreateView):
    """
    View to create new account address
    """
    template_name = "accounts/address_create.html"
    form_class = AddressForm
    model = Address
    success_url = reverse_lazy('accounts:my_address')
    success_message = "Address was added successfully"

    def form_valid(self, form):
        """
        Assign the account to the request.user
        """
        form.instance.account = self.request.user
        form.instance.active = False
        return super(AddressCreateView, self).form_valid(form)

Answer 1

我发现问题出在HTML文件中，有一些剩余的AJAX。我正在尝试一些事情，我在HTML的form标签类中添加了address_form，并进行了AJAX调用。因此，AJAX和HTTP调用都会发生。我从表单标签的类中删除了address_form，问题就消失了。

<form class="form-horizontal" method="post">

更改为：

$(document).ready(function () {
  var $addressForm = $('.address_form')
  $addressForm.submit(function(event){
      event.preventDefault()
      var $formData = $(this).serialize()
      var $endpoint = $addressForm.attr("data-url")
      $.ajax({method: "POST", url: $endpoint, 
         data: $formData, 
         success: handleFormSuccess,
         error: handleFormError,
     })

  })

以后是一些javascript

putchar

Django CreateView success_url失败

1 个答案: