Question

我有一张如下表格。我需要将行转换为列。我知道我可以通过工会选择5次。我正在寻找有关如何使用pivot

执行此操作的建议

ID    NAME   TAG    TAG_1   TAG_2   TAG_3   TAG_4  LOCATION
10    test   abc    abc_1   abc_2   abc_3   abc_4  china

ID    NAME    TAG        LOCATION
10    test    abc        china
10    test    abc_1      china
10    test    abc_2      china
10    test    abc_3      china
10    test    abc_4      china

with t as (
 select ID, name, tag,location from table_one
 )
 select * from t
 unpivot (
 value for tag in (tag_1,tag_2,tag_3,tag_4
 )

我尝试使用上面的unpivot，我收到列名称（tag_1，tag_2）的无效标识符ORA-00904错误。声明中有什么问题。

Answer 1

在SQL SERVER 2008中：

'date'

Answer 2

我希望我能正确地回答你的问题。你可以在oracle中使用PIVOT来做到这一点。试试这个。如果需要，您可以在PIVOT子句中向列表中添加更多内容。

SELECT *
FROM (SELECT 10 AS id, 'test' AS name, 'abc_1' AS tag, 'china' AS location FROM DUAL
      UNION
      SELECT 10 AS id, 'test' AS name, 'abc_2' AS tag, 'china' AS location FROM DUAL
      UNION
      SELECT 10 AS id, 'test' AS name, 'abc_3' AS tag, 'china' AS location FROM DUAL
      UNION
      SELECT 10 AS id, 'test' AS name, 'abc_4' AS tag, 'china' AS location FROM DUAL
      UNION
      SELECT 10 AS id, 'test' AS name, 'abc_5' AS tag, 'china' AS location FROM DUAL
      UNION
      SELECT 20 AS id, 'test' AS name, 'abc_2' AS tag, 'china' AS location FROM DUAL
      UNION
      SELECT 20 AS id, 'test' AS name, 'abc_4' AS tag, 'china' AS location FROM DUAL
      UNION
      SELECT 20 AS id, 'test' AS name, 'abc_6' AS tag, 'china' AS location FROM DUAL
      UNION
      SELECT 30 AS id, 'test' AS name, 'abc_1' AS tag, 'china' AS location FROM DUAL
      UNION
      SELECT 30 AS id, 'test' AS name, 'abc_3' AS tag, 'china' AS location FROM DUAL
      UNION
      SELECT 30 AS id, 'test' AS name, 'abc_5' AS tag, 'china' AS location FROM DUAL)
     PIVOT (MAX (tag) AS tag FOR (tag) IN ('abc_1' AS t1, 'abc_2' AS t2, 'abc_3' AS t3, 'abc_4' AS t4, 'abc_5' AS t5, 'abc_6' AS t6))

ORDER BY id，name，location;

Answer 3

create table test_pivot
(TID  number,
Tname  varchar2(10),
Tag_1  varchar2(10),
Tag_2  varchar2(10),
Tag_3   varchar2(10),
Tag_4    varchar2(10),
Tag_5    varchar2(10),
T_Location  varchar2(10)
);


insert into test_pivot(TID,
Tname,
Tag_1,
Tag_2,
Tag_3,
Tag_4,
Tag_5,
T_Location
)
values(10,'Test','ABC','PQR','TUV','LMN','XYZ','INDIA');


select * from test_pivot;

select *
from test_pivot
unpivot(value for tag in (Tag_1 as 'Tag_1',
Tag_2 as 'Tag_2',
Tag_3 as 'Tag_3',
Tag_4 as 'Tag_4',
Tag_5 as 'Tag_5')
)

Answer 4

    with t as (
     select ID, name, tag, tag_1, tag_2, tag_3, tag_4, location from table_one
     )
     select * from t
     unpivot (
     value for _tag_ in (tag,tag_1,tag_2,tag_3,tag_4)
     )

编辑：确定了OP的sql中的三个问题：

WITH子句不包含列TAG_1 .. TAG_4，但它们已包含在UNPIVOT子句中。

with t as (
 select ID, name, tag,location from table_one
 )

UNPIVOT子句正在使用现有列TAG来收集TAG_1到TAG_4的值。

 unpivot (
 value for tag in (tag_1,tag_2,tag_3,tag_4
 )

预期结果集显示TAG中的值，但未在IN块中列出。

（tag_1，tag_2，tag_3，tag_4
中标记的值）

将行转换为列sql

4 个答案: