这是我用来发布id的值并在下一页上重现该id的代码
<?php
global $row6;
$query= "select s.name ,s1.price from services s ,seller_services s1 where s1.service_id = s.id LIMIT 7;";
$result= mysqli_query($conn3,$query) or die(mysqli_error($conn3));
while($row6=mysqli_fetch_array($result))
{
?>
<div class="col-md-3 col-sm-4">
<div class="pro-box">
<div class="pro-thumb"><img src="https://udemy-images.udemy.com/course/240x135/1192700_6496_2.jpg" alt=""></div>
<div class="pro-txt"> <a href="#" class="add2cart"><i class="fa fa-shopping-cart"></i></a>
<h6><a href=""><?php echo $row6['name'];?></a></h6>
<p class="price"><i class="fa fa-inr" aria-hidden="true"></i><?php echo $row6['price'];?></p>
<form action="manageservice.php" method="POST">
<button name="buy"><input type="submit" hidden="id" value="buy" name="buy"/></button>
</form>
<div class="pro-rating"><a href="#"><i class="fa fa-star"></i> <i class="fa fa-star"></i> <i class="fa fa-star"></i> <i class="fa fa-star"></i> <i class="fa fa-star"></i></a></div>
</div>
</div>
</div>
<?php } ?>
这是我用来接收id的值的代码，但它没有显示任何我不知道的
<div class="team-page">
<div class="container">
<div class="row">
<?php
global $row;
if(isset($_POST['buy']))
{
$id=$_POST['id'];
$query5= "Select *from services where id = '$id'; ";
$result=mysqli_query($conn3,$query5) or die("Mysql error");
while($row=mysqli_fetch_array($result))
{
?>
<!--Team Box Start-->
<div class="col-md-3 col-sm-6">
<div class="team-box">
<div class="thumb">
<div class="team-hover">
<h6>Michelle WU</h6>
<p>Aliquam nec finibus dui, eget dapibus leo. Suspendisse aliquam, justo in venenatis congue, sem odio vestibulum lorem, quis consectetur arcu nulla in est. </p>
<div class="mayor-social"> <a class="fb" href="#"><i class="fa fa-facebook"></i></a> <a class="tw" href="#"><i class="fa fa-twitter"></i></a> <a class="lin" href="#"><i class="fa fa-linkedin"></i></a> <a class="yt" href="#"><i class="fa fa-youtube"></i></a> </div>
</div>
<img src="images/timg-1.jpg" alt=""></div>
<div class="team-txt">
<h5><?php echo $row['name'];?></h5>
<p><?php echo $row['email'];?></p>
</div>
</div>
<div class="loc-footer" style="background-color:#fff;">
<ul>
<li class="loc-rating">4.98 <i class="fa fa-star"></i> <i class="fa fa-star"></i> <i class="fa fa-star"></i> <i class="fa fa-star"></i> <i class="fa fa-star-half-o"></i></li>
<li class="more">
<div class="btn-group dropup">
<button type="button" data-toggle="dropdown"> <i class="fa fa-ellipsis-h"></i> </button>
<ul class="dropdown-menu">
<li><a href="#"><i class="fa fa-envelope-o"></i> Send Email</a></li>
<li><a href="#"><i class="fa fa-commenting-o"></i> Send Message</a></li>
<li><a href="#"><i class="fa fa-compass"></i>Request a Call Back</a></li>
</ul>
</div>
</li>
</ul>
</div>
</div>
<?php } ?>
<?php } ?>
所以现在的问题是，id不会收到任何价值或者我无法弄清楚该怎么做的事情请帮助人们
答案 0 :(得分：0)
根据我以前的不完整答案：我认为您的问题是您尝试显示$row的值，但是在while($row=mysqli_fetch_array($result))循环之外。我试图修复你的代码。尝试一下，让我知道它是否正常工作，或者是否有任何错误。
<div class="team-page">
<div class="container">
<div class="row">
<?php
global $row;
if(isset($_POST['buy'])) {
$id=$_POST['id'];
$query5= "Select *from services where id = '$id'; ";
$result=mysqli_query($conn3,$query5) or die("Mysql error");
}
?>
<!--Team Box Start-->
<div class="col-md-3 col-sm-6">
<div class="team-box">
<div class="thumb">
<div class="team-hover">
<h6>Michelle WU</h6>
<p>Aliquam nec finibus dui, eget dapibus leo. Suspendisse aliquam, justo in venenatis congue, sem odio vestibulum lorem, quis consectetur arcu nulla in est. </p>
<div class="mayor-social"> <a class="fb" href="#"><i class="fa fa-facebook"></i></a> <a class="tw" href="#"><i class="fa fa-twitter"></i></a> <a class="lin" href="#"><i class="fa fa-linkedin"></i></a> <a class="yt" href="#"><i class="fa fa-youtube"></i></a> </div>
</div>
<img src="images/timg-1.jpg" alt=""></div>
<div class="team-txt">
<?php
while($row=mysqli_fetch_array($result)) {
?>
<h5><?php echo $row['name'];?></h5>
<p><?php echo $row['email'];?></p>
<?php } ?>
</div>
</div>