基于另一个JSON对象的值访问JSON对象

时间:2018-04-13 13:05:32

标签: javascript jquery json

请原谅我的主题。无法理解要放什么。

我有一些动态生成的数据。数据与此类似。

var TypeA ={ "length" : "100" , "width" :"80" , "color" : "#ffffff" }    
var TypeB ={ "length" : "150" , "width" :"120" , "color" : "#4286f4" }
var TypeC ={ "length" : "150" , "width" :"120" , "color" : "#4202f4" }

以上几个JSON分别定义了类型A,B,C的属性。 (实际上,有很多种类型。)

现在我有如下实际数据:

 var data =[{id : "1" , label : "A1" , type : "TypeA" },
            {id : "2" , label : "A2" , type : "TypeA" },
            {id : "3" , label : "B1" , type : "TypeB" },
            {id : "4" , label : "A3" , type : "TypeA" },
            {id : "5" , label : "C1" , type : "TypeC" },
            {id : "6" , label : "B2" , type : "TypeB" }
            ]

现在我在data中运行循环。在此循环中,我需要根据数据JSON中定义的type访问Type属性。

我正在做这样的事情,但它似乎无法奏效。

$.each(JSON.parse(data), function(index,jsonObject){
      console.log("ColorCode : "+ jsonObject.type.color);
 });

任何人都可以帮助我如何在这里访问类型属性。感谢。

3 个答案:

答案 0 :(得分:3)

在您给出的示例中,您为每个类型定义定义了一个变量。它使他们更难以访问。相反,你应该有这个:

var types = {
  "TypeA": { "length" : "100" , "width" :"80" , "color" : "#ffffff" },
  "TypeB": { "length" : "150" , "width" :"120" , "color" : "#4286f4" },
  "TypeC": { "length" : "150" , "width" :"120" , "color" : "#4202f4" }
};

或者这个:

var TypeA ={ "length" : "100" , "width" :"80" , "color" : "#ffffff" };  
var TypeB ={ "length" : "150" , "width" :"120" , "color" : "#4286f4" };
var TypeC ={ "length" : "150" , "width" :"120" , "color" : "#4202f4" };
var types = {
  "TypeA": TypeA,
  "TypeB": TypeB,
  "TypeC": TypeC
};

然后,这很容易做到:

JSON.parse(data).forEach(function(el) {
  console.log("ColorCode : " + types[el.type].color);
});

演示



var types = {
  "TypeA": { "length": "100", "width": "80", "color": "#ffffff" },
  "TypeB": { "length": "150", "width": "120", "color": "#4286f4" },
  "TypeC": { "length": "150", "width": "120", "color": "#4202f4" }
};

var data =[
  {id : "1" , label : "A1" , type : "TypeA" },
  {id : "2" , label : "A2" , type : "TypeA" },
  {id : "3" , label : "B1" , type : "TypeB" },
  {id : "4" , label : "A3" , type : "TypeA" },
  {id : "5" , label : "C1" , type : "TypeC" },
  {id : "6" , label : "B2" , type : "TypeB" }
];

data.forEach(function (el) {
  console.log("ColorCode : " + types[el.type].color);
});




答案 1 :(得分:1)

我建议您在对象中定义Type

var obj = {
  "TypeA": {.... },
  "TypeB": {.... },,
  "TypeC": {.... },
};

然后您可以轻松使用Bracket notation来访问基于属性的字符串键。

 $.each(data, function(index,jsonObject){
      console.log("ColorCode : ", obj[jsonObject.type].color);
 });

var obj = {
  "TypeA": {
    "length": "100",
    "width": "80",
    "color": "#ffffff"
  },
  "TypeB": {
    "length": "150",
    "width": "120",
    "color": "#4286f4"
  },
  "TypeC": {
    "length": "150",
    "width": "120",
    "color": "#4202f4"
  }
};

var data = [{
    id: "1",
    label: "A1",
    type: "TypeA"
  },
  {
    id: "2",
    label: "A2",
    type: "TypeA"
  },
  {
    id: "3",
    label: "B1",
    type: "TypeB"
  },
  {
    id: "4",
    label: "A3",
    type: "TypeA"
  },
  {
    id: "5",
    label: "C1",
    type: "TypeC"
  },
  {
    id: "6",
    label: "B2",
    type: "TypeB"
  }
]

 $.each(data, function(index,jsonObject){
      console.log("ColorCode : ", obj[jsonObject.type].color);
 });
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>

答案 2 :(得分:-2)

使用window调用变量。

var TypeA ={ "length" : "100" , "width" :"80" , "color" : "#ffffff" }    
var TypeB ={ "length" : "150" , "width" :"120" , "color" : "#4286f4" }
var TypeC ={ "length" : "150" , "width" :"120" , "color" : "#4202f4" }

var dataO = [{id : "1" , label : "A1" , type : "TypeA" },
            {id : "2" , label : "A2" , type : "TypeA" },
            {id : "3" , label : "B1" , type : "TypeB" },
            {id : "4" , label : "A3" , type : "TypeA" },
            {id : "5" , label : "C1" , type : "TypeC" },
            {id : "6" , label : "B2" , type : "TypeB" }];

/*The data is already parsed.*/

dataO.forEach(function(key, index){
  console.log(window[key.type].color);
});

/*dataO.forEach(key => console.log(window[key.type].color));*/