Question

我正在运行一个命令来将机器添加到域中，一切正常。

我现在想从参数值中取$string1中的值，有没有办法做到这一点？

$rg = "resourcegroup"
$machines = Get-AzureRmVM -ResourceGroupName $rg

$string1 ='{
  "Name" : "domain.local",
  "User": "domain.local\\domainadmin",
  "Restart" : "true",
  "Options" : "3",
}'

$string2 = '{"Password" : "@@@@@@@@@@@@@B"}'

$machines | ForEach { Set-AzureRmVMExtension -ResourceGroupName $rg
  -ExtensionType "JSONADDomainExtension" -Name "joindomain"
  -Publisher "Microsoft.Compute" -TypeHandlerVersion "1.0" -VMName $_.Name
  -Location "uk west" -SettingString $string1 -ProtectedSettingString $String2 }

Answer 1

构建自定义对象并将其转换为JSON。这样你就可以避免任何和所有转义问题，并且因为输入是实际的PowerShell代码，所以改变对象的任何部分都是微不足道的：

[pscustomobject] @{
  Name = 'domain.local'
  User = 'domain.local\domainadmin'
  Restart = 'true'
  Options = '3'
} | ConvertTo-Json

产生以下结果：

{
    "Name":  "domain.local",
    "User":  "domain.local\\domainadmin",
    "Restart":  "true",
    "Options":  "3"
}

Answer 2

诀窍似乎是通过加倍来摆脱花括号。

$string1 ='{{
  "Name" : "{0}",
  "User": "{1}",
  "Restart" : "{2}",
  "Options" : "{3}"
}}' -f 'domain.local', 'domain.local\\domainadmin', 'true', '3'

Answer 3

只需连接字符串和参数变量：

param (
    [string]$name
)


$string1 ='{
  "Name" : "' + $name +'",
  "User": "domain.local\\domainadmin",
  "Restart" : "true",
  "Options" : "3",
}'

如何在powershell中将参数传递给字符串变量

3 个答案: