Question

我在AsyncTask中读取URL的内容时遇到问题：

    String cont="";
    asyncT t = new asyncT();

    try {
        cont = t.execute("http://wardenlotro.epizy.com/").get();
    }
    catch (Exception e){
        e.printStackTrace();
    }

在主要活动中：

<html><body><script type="text/javascript" src="/aes.js" ></script><script>function toNumbers(d){var e=[];d.replace(/(..)/g,function(d){e.push(parseInt(d,16))});return e}function toHex(){for(var d=[],d=1==arguments.length&&arguments[0].constructor==Array?arguments[0]:arguments,e="",f=0;f<d.length;f++)e+=(16>d[f]?"0":"")+d[f].toString(16);return e.toLowerCase()}var a=toNumbers("f655ba9d09a112d4968c63579db590b4"),b=toNumbers("98344c2eee86c3994890592585b49f80"),c=toNumbers("202588dd6fbc15306fac1235140f8b84");document.cookie="__test="+toHex(slowAES.decrypt(c,2,a,b))+"; expires=Thu, 31-Dec-37 23:55:55 GMT; path=/"; location.href="http://wardenlotro.epizy.com/?i=1";</script><noscript>This site requires Javascript to work, please enable Javascript in your browser or use a browser with Javascript support</noscript></body></html>

我需要网络内容，但我明白了：

echo "Hi World";

服务器中的index.php文件现在只有122 55 122 56 122.5 57 > 123 25.25 123 25.27

HttpURLConnection不接受内容网站

0 个答案: