Question

我正在收到这样的JSON响应：

{
    "partner_wise": {
        “partner1”: {
            "processing": 254,
            "complete": 0,
            "track_invoice": 0,
            "bar_code": 0
       },
        "": {
            "processing": 0,
            "complete": 0,
            "track_invoice": 0,
            "bar_code": 0
             },
        “partner2”: {
            "processing": 0,
            "complete": 0,
            "track_invoice": 0,
            "bar_code": 0
        }
      }
}

我在tableView中以索引方式设置这些值。从这个JSON响应中，我没有必要显示哪个键是空字符串的值。如何从NSDictionary中删除此对象。

Answer 1

您无法从NSDictionary中删除这些对象。 NSDictionary是一个不可变的对象但是你可以制作一个可变副本并删除不需要的密钥：

10.3

Answer 2

您可以使用removeObjectForKey

[dictionary removeObjectForKey:@""];

示例代码：

//your json dictionary here!
NSDictionary *finalDictionary = [[NSDictionary alloc] initWithObjectsAndKeys:@"11111111",@"",@"00000000",@"testkey1", nil];

NSMutableDictionary *dictionaryColection = [[NSMutableDictionary alloc] initWithDictionary:finalDictionary];
NSLog(@"Dictionary Full: %@", dictionaryColection);

[dictionaryColection removeObjectForKey:@""];
finalDictionary = dictionaryColection;
NSLog(@"Final dictionary removed: %@", finalDictionary);

日志：

Dictionary Full: {
    "" = 11111111;
    testkey1 = 00000000;
}

Final dictionary removed: {
    testkey1 = 00000000;
}

Answer 3

在swift 3.0中

dictionary.removeObject(forKey: "")

从NSDictionary中删除Key为空字符串的值

3 个答案: