Question

＆＃13;

<table>
        <tr>
            <th>name</th>
            <th>sum(value)</th>
         </tr>
         <tr>
            <td>null</td>
            <td>85</td>
         </tr>
         <tr>
            <td>arun</td>
            <td>74</td>
        </tr>
        <tr>
            <td>dhin</td>
           <td>55</td>
       </tr>
    </table>

＆＃13;

我有一个像上面这样的表数据。我想基于sum（value）desc排序项目，如果名称为null，则必须最后显示。如何在mysql中编写查询

我的查询是SELECT p.class，p.buyref，p.no_of_mat_id，p.tot_cos from（select a.class，group_concat（distinct a.buyref SEPARATOR＆＃39;＆＃34;，＆＃34;＆＃39;）as buyref，count（*）as no_of_mat_id，sum（tc）as tot_cos from（select a.class，a.buyref，sum（b.total_cost）as tc from（SELECT distinct a.class，b.buyref来自material_master来自a.cat_id = b.cat_id的加入rxml_reference b，其中a.language =＆＃39; 0161-1＃LG-000001＃1＆＃39;和b.property =＆＃ 39;买家参考＆b;和b.buyref＆lt;＆gt;＆＃39;＆＃39;和b.buyref in（＆＃34; E268200006＆＃34;，＆＃34; E570500008＆＃34;，＆＃34; E330010072＆＃34;＆＃34; 1274266＆＃34;＆＃34; 1257657＆＃34;＆＃34; 1216933＆＃34;＆＃34; 1275795＆＃34;＆＃34; 1269085＆＃34 ;, ＆＃34; 1216931＆＃34;＆＃34; 1257656＆＃34;＆＃34; 1213833＆＃34;＆＃34; 5066725＆＃34;＆＃34; 1275794＆＃34;＆＃34; 5067252＆＃34;＆＃34; 1257658＆＃34;＆＃34; 1236240＆＃34;＆＃34; 1274249＆＃34;＆＃34; 1213824＆＃34;＆＃34; 1275797＆＃34;，＆＃34; 5067664＆＃34;＆＃34; 1236239＆＃34;＆＃34; 1248625＆＃34;＆＃34; 1275796＆＃34;＆＃34; 5066724＆＃34;＆＃34; 5065949＆＃ 34;，＆＃34; 1213989＆＃34;＆＃34; 1216932＆＃34;＆＃34; 1257659＆＃34;＆＃34; 122 7545＆＃34;＆＃34; 1280565＆＃34;＆＃34; 1280549＆＃34;＆＃34; 1213829＆＃34;＆＃34; 1264792＆＃34;＆＃34; 1280550＆＃34 ;, ＆＃34; 1280551＆＃34;＆＃34; 1216943＆＃34;＆＃34; 1249846＆＃34;＆＃34; 1210250＆＃34;＆＃34; 1282003＆＃34;＆＃34; 1248620＆＃34;＆＃34; 5065948＆＃34;＆＃34; 1213830＆＃34;＆＃34; 1216942＆＃34;＆＃34; 1210217＆＃34;＆＃34; 1210247＆＃34;，＆＃34; 1279855＆＃34;＆＃34; 1280567＆＃34;＆＃34; 1280553＆＃34;＆＃34; 1210292＆＃34;＆＃34; 1281546＆＃34;＆＃34; 1213846＆＃ 34;，＆＃34; 1238253＆＃34;＆＃34; 1210323＆＃34;＆＃34; 1264791＆＃34;＆＃34; 5065610＆＃34;＆＃34; 1217304＆＃34;＆＃ 34; 1216973＆＃34;＆＃34; 1271479＆＃34;＆＃34; 1285240＆＃34;＆＃34; 1217303＆＃34;＆＃34; 5063937＆＃34;＆＃34; 5063934＆＃34 ;，＆＃34; 1285241＆＃34;＆＃34; 1238255＆＃34;＆＃34; 1280552＆＃34;＆＃34; 1280566＆＃34;＆＃34; 1292638＆＃34;＆＃34 ; 5075432＆＃34;＆＃34; 1292635＆＃34;＆＃34; 1293721＆＃34;＆＃34; 1258418＆＃34;＆＃34; 1290188＆＃34;＆＃34; 5071130＆＃34; ＆＃34; 1292061＆＃34;＆＃34; 1258417＆＃34;＆＃34; 1292634＆＃34;＆＃34; 1292631＆＃34;＆＃34; 1292632＆＃34;＆＃34; 1292633＆＃34;＆＃34; 1292639＆＃34;＆＃34; 1292060＆＃34;＆＃34; 5071580＆＃34;＆＃34; 1293251＆＃34;＆＃34; 5075431＆＃34 ;, ＆＃34; 1292597＆＃34;＆＃34; 36066＆＃34;＆＃34; 1268083＆＃34;＆＃34; 1219900＆＃34;＆＃34; 49194＆＃34;＆＃34; 46646＆＃34;＆＃34; 1272051＆＃34;＆＃34; 48743＆＃34;＆＃34; 1219891＆＃34;＆＃34; 49604＆＃34;＆＃34; 41693＆＃34;，＆＃34; 1247650＆＃34;＆＃34; 1241850＆＃34;＆＃34; 41728＆＃34;＆＃34; 49588＆＃34;＆＃34; 1258736＆＃34;＆＃34; 44917＆＃ 34;，＆＃34; 1219898＆＃34;＆＃34; 1266629＆＃34;＆＃34; 39660＆＃34;＆＃34; 1267486＆＃34;＆＃34; 1270445＆＃34;＆＃ 34; 1222352＆＃34;＆＃34; 1259901＆＃34;＆＃34; 36074＆＃34;＆＃34; 1272388＆＃34;＆＃34; 1275153＆＃34;＆＃34; 1240833＆＃34 ;，＆＃34; 1237806＆＃34;＆＃34; 46645＆＃34;＆＃34; 1219897＆＃34;＆＃34; 1271400＆＃34;＆＃34; 1272385＆＃34;＆＃34 ; 41066＆＃34;＆＃34; 36073＆＃34;＆＃34; 1244303＆＃34;＆＃34; 1241848＆＃34;＆＃34; 41730＆＃34;＆＃34; 1220612＆＃34; ＆＃34; 45332＆＃34;＆＃34; 41565＆＃34;＆＃34; 49204＆＃34;＆＃34; 1244246＆＃34;＆＃34; 45329＆＃34;＆＃34; 1272384＆＃34;＆＃34; 1222919＆＃34;＆＃34; 1231947＆＃34;＆＃34; 1225515＆＃34;＆＃34; 1272052＆＃34;＆＃34; 1271399＆＃34 ;, ＆＃34; 49664＆＃34;＆＃34; 46118＆＃34;＆＃34; 1241847＆＃34;＆＃34; 49691＆＃34;＆＃34; 1219899＆＃34;＆＃34; 1273498＆＃34;＆＃34; 52919＆＃34;＆＃34; 46350＆＃34;＆＃34 ; 49201＆＃34;＆＃34; 1272750＆＃34;＆＃34; 1237807＆＃34;＆＃34; 29632＆＃34;＆＃34; 1220800＆＃34;＆＃34; 36481＆＃34; ＆＃34; 41709＆＃34;＆＃34; 1276924＆＃34;＆＃34; 40133＆＃34;＆＃34; 36062＆＃34;＆＃34; 36268＆＃34;＆＃34; 49684＆＃34;＆＃34; 1273492＆＃34;＆＃34; 1276923＆＃34;＆＃34; 36302＆＃34;＆＃34; 1281374＆＃34;＆＃34; 49603＆＃34 ;, ＆＃34; 1219892＆＃34;，＆＃34; 49480＆＃34;））在a.buyref = b.item上加入final_transaction b，其中b.accounting_date＆gt; =＆＃39; 2014-1-01 00:00 ：00＆＃39;和b.accounting_date＆lt; =＆＃39; 2018-4-31 00：00：00＆＃39;和b.supplier_id（＆＃39; GLOBL-ASP01-0000005443＆＃39;，＆＃39; GLOBL-ASP01-0000005443＆＃39;＆＃39; GLOBL-NFT01-0000124166＆＃39;，＆＃39; GLOBL -ASP01-0000001239＆＃39;，＆＃39; APCPM-APCPM-A0012496＆＃39;，＆＃39; GLOBL-ASP01-0000001643＆＃39;＆＃39; ACM_388437＆＃39;＆＃39; ACM_11590352＆＃39 ;，＆＃39; ACM_5174231＆＃39; ECM_18494＆＃39;）按a.class分组，a.buyref）按a.class顺序分组sum（tc）desc）p ORDER BY p.tot_cos降序

Answer 1

SELECT name,SUM(value) 
FROM TABLE1
ORDER BY CASE WHEN name IS NULL THEN 1 ELSE 0 END,SUM(value) Desc

<强>输出

name    sum_value
trun    84
arun    74
dhin    55
(null)  85

演示链接

http://sqlfiddle.com/#!9/fa6eb7/1

1 个答案: