我一直得到相同的错误代码ORA-00933

Question

我不太确定这是怎么回事。我将得到代码＆＃34; 00907缺少右括号＆＃34;所以，我添加了括号，然后我会得到＆＃34; 00933错误＆＃34;

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Answer 1

你应该尝试这个：

在要使用的列的列名称之前放置表的别名或名称。

在这里，我假设您希望RENTER_ID表中的RENTER。

SELECT RENTER.RENTER_ID,
  RENTER_LNAME,
  ROUND((COUNT(DEP_ID)+1)/APART_BED) AS "PEOPLE / BEDROOM"
FROM RENTER
    JOIN DEPENDENT
        ON RENTER.RENTER_ID = DEPENDENT.RENTER_ID
    JOIN LEASE
        ON LEASE.RENTER_ID = RENTER.RENTER_ID
    JOIN APARTMENT
        ON APARTMENT.APART_NUM = LEASE.APART_NUM
    WHERE RENTER.RENTER_ID        = LEASE_END
      AND RENTER.RENTER_ID          = '30-JUN-18'
    ORDER BY RENTER_ID;

Answer 2

您在WHERE CLAUSE中有语法错误，您无法写：

 WHERE RENTER_ID = ((LEASE_END) = '30-JUN-18')

您必须编写两个单独的条件，例如：

WHERE RENTER.RENTER_ID = LEASE.RENTER_ID
AND LEASE.LEASE_END = '30-JUN-18'

示例查询：

SELECT RENTER.RENTER_ID,
       RENTER_LNAME,
       Round((Count(DEP_ID) + 1) / APART_BED) AS "PEOPLE / BEDROOM"
  FROM RENTER
  JOIN DEPENDENT
    ON RENTER.RENTER_ID = DEPENDENT.RENTER_ID
  JOIN LEASE
    ON LEASE.RENTER_ID = RENTER.RENTER_ID
  JOIN APARTMENT
    ON APARTMENT.APART_NUM = LEASE.APART_NUM
 WHERE RENTER.RENTER_ID = DEPENDENT.RENTER_ID
 AND LEASE.LEASE_END = '30-JUN-18'
 ORDER BY RENTER_ID;

Answer 3

SELECT  RENTER.RENTER_ID,
    RENTER_LNAME,
    Round((Count(DEP_ID)+1)/APART_BED) AS "PEOPLE / BEDROOM"
FROM RENTER JOIN DEPENDENT ON RENTER.RENTER_ID = DEPENDENT.RENTER_ID
        JOIN LEASE ON LEASE.RENTER_ID = RENTER.RENTER_ID
        JOIN APARTMENT ON APARTMENT.APART_NUM = LEASE.APART_NUM
WHERE RENTER_ID = LEASE_END AND RENTER_ID = '30-JUN-18'
ORDER BY RENTER_ID;