Question

如果数据库中已存在以下项目：'email', 'youtube_channel_username', 'youtube_channel_url', 'youtube_channel_title'，如何防止 POST 请求被保存？实际上，我想添加一个验证步骤，确保用户尝试发布的内容对于上述内容是唯一的。理想情况下，服务器应向用户发回错误消息，通知他们他们的请求因任何原因而失败。

到目前为止，这是我的代码。我不知道在哪里添加此功能，所以我将不胜感激！

serializers.py

class CreatorSignupSerializer(serializers.Serializer):
    """
    Create Creator profile
    """
    first_name = serializers.CharField(required=True, write_only=True)
    last_name = serializers.CharField(required=True, write_only=True)
    email = serializers.CharField(required=True, write_only=True)
    youtube_channel_username = serializers.CharField(required=True, write_only=True)
    youtube_channel_url = serializers.CharField(required=True, write_only=True)
    youtube_channel_title = serializers.CharField(required=True, write_only=True)
    youtube_channel_description = serializers.CharField(required=True, write_only=True)
    photo = serializers.CharField(required=True, write_only=True)
    youtube_channel_start_date = serializers.CharField(required=True, write_only=True)
    keywords = serializers.CharField(required=True, write_only=True)
    no_of_subscribers = serializers.IntegerField(required=True, write_only=True)
    no_of_videos = serializers.IntegerField(required=True, write_only=True)
    no_of_views = serializers.IntegerField(required=True, write_only=True)
    no_of_likes = serializers.IntegerField(required=True, write_only=True)
    no_of_dislikes = serializers.IntegerField(required=True, write_only=True)
    location = serializers.CharField(required=True, write_only=True)
    avg_views = serializers.IntegerField(required=True, write_only=True)
    gender = serializers.IntegerField(required=True, write_only=True)
    password = serializers.CharField(required=True, write_only=True)

    class Meta:
        model = Creator
        fields = (
            'first_name', 'last_name', 'email', 'youtube_channel_username', 'youtube_channel_url',
            'youtube_channel_title', 'youtube_channel_description', 'photo', 'youtube_channel_start_date', 'keywords',
            'no_of_subscribers', 'no_of_videos', 'no_of_views', 'no_of_dislikes', 'no_of_likes' 'location', 'avg_views',
            'gender', 'password',
        )
        read_only_fields = 'id'

    def create(self, validated_data):
        creator = Creator.objects.create(**validated_data)
        creator.save()
        return creator

    def update(self, instance, validated_data):
        pass

views.py

class CreatorSignup(generics.CreateAPIView):
    """
    Creator signup
    HTTP POST
    """
    queryset = Creator.objects.all()
    serializer_class = CreatorSignupSerializer

    def post(self, request, *args, **kwargs):
        return self.create(request, *args, **kwargs)

    def create(self, request, *args, **kwargs):
        serializer = self.get_serializer(data=request.data)
        serializer.is_valid(raise_exception=True)
        return Response(data=serializer.data, status=status.HTTP_201_CREATED)

Answer 1

您可以非常轻松地在模型级别实现独特验证。您只需要覆盖save以调用full_clean方法（如果您在模型级别进行任何其他验证）。此外，作为注释，它将抛出django.exceptions.ValidationError并且您可以配置DRF以捕获django.exceptions.ValidationError并将其转换为rest_framework.exceptions.ValidationError，然后DRF将自动发回400错误消息。 / p>

# models.py
class User(AbstractBaseUser, PermissionsMixin):
    email = models.EmailField(max_length=255, unique=True)  # NOTE unique=True
    first_name = models.CharField(max_length=30)
    last_name = models.CharField(max_length=30)
    phone = models.CharField(max_length=20)

    def save(self, *args, **kwargs):
        self.full_clean()
        return super().save(*args, **kwargs)

Answer 2

如何在模型的Meta类中添加>>> timeit.timeit('foo[stop_idx:start_idx+1][::-1]', setup='foo="012345"; stop_idx=0; start_idx=3', number=10_000_000) 1.7157553750148509 >>> timeit.timeit('foo[start_idx:stop_idx-len(foo)-1:-1]', setup='foo="012345"; stop_idx=0; start_idx=3', number=10_000_000) 1.9317215870250948，如下所示

unique_together

注意：如果添加此项，则无需在序列化程序中定义任何特殊的验证方法

如果特定列不唯一，则拒绝POST请求

2 个答案: