Question

我认为最好分一些地提出这些问题而不是一个大问题。这是之前已解决的问题的延续。我有以下查询提取每个国家/地区的国家/地区和计数。

$query = mysqli_query($con, "SELECT COUNT(id) AS countCnt, country FROM users GROUP BY country ORDER BY COUNT(id) DESC");

我试图在数组中获取这些内容，如下所示我可以将它们分配为变量：

$country_text = ['USA', 'Canada', 'England', 'Australia', 'New Zealand', etc...];
$country_count = [15, 10, 5, 3, 2, etc...];

一旦分配了这些，我想按如下方式显示它们：

    for($i = 0; $i < 195; $i++) {

    echo "['{$country_text[$i]}'" . "," . "{$country_count[$i]}],";
}

这三个代码链接在一起是完整的。我所面临的挑战是创建数组＆amp;将它们指定为变量。任何帮助将不胜感激。

Answer 1

您可以通过以下方式实现此目的：

//do a query and run
$query = mysqli_query($con, "SELECT COUNT(id) AS countCnt, country FROM users GROUP BY country ORDER BY COUNT(id) DESC");

$countries = [];

//iterate through values from query
while($row = mysqli_fetch_assoc($query)) {
    $country = $row['country'];
    $countryCount = $row['countCnt'];
    //create and array with data, formatted as ['USA' => '15', 'Canada' => '10' , ...]
    $countries[$country] = $countryCount;
}

//Create both arrays
$country_text = array_keys($countries);
$country_count = array_values($countries);

或者，而不是做

for($i = 0; $i < 195; $i++) {
    echo "['{$country_text[$i]}'" . "," . "{$country_count[$i]}],";
}

你可以做到

foreach($countries as $country => $count) {
    echo "[".$country." ," .$count."],";
}

Answer 2

您需要的格式称为$query = mysqli_query($con, "SELECT COUNT(id) AS countCnt, country FROM users GROUP BY country ORDER BY COUNT(id) DESC"); $countries = []; while($row = mysqli_fetch_assoc($query)) { $countries[] = [$row['country'], $row['countCnt']]; } echo json_encode($countries);。不要发明轮子，一切都已经发明了：

sparkR.session(sparkConfig = list(spark.cores.max='2',spark.executor.memory = '8g'))

从mySQLli Query创建数组以在php中显示

2 个答案: