我很好奇如何将此查询转换为Laravel查询。
这是我在phpmyadmin上尝试过的附近查询。
set @lat=37.034126;
set @lng=27.430235;
SELECT party_title, latitude, longitude, 111.045 * DEGREES(ACOS(COS(RADIANS(@lat))
* COS(RADIANS(latitude))
* COS(RADIANS(longitude) - RADIANS(@lng))
+ SIN(RADIANS(@lat))
* SIN(RADIANS(latitude))))
AS distance_in_km
FROM parties
ORDER BY distance_in_km ASC
LIMIT 0,5
查询结果:
我试过这样但它没有用。
public function index(\Illuminate\Http\Request $request) {
if($request->has('party_category')){
$parties = Parties::where('party_category', $request->party_category)->get();//your new query here
}
else if($request->has('lat') && $request->has('long')){
$parties = Parties::whereRaw("ACOS(SIN(RADIANS('latitude'))*SIN(RADIANS($request->lat))+COS(RADIANS('latitude'))*COS(RADIANS($request->lat))*COS(RADIANS('longitude')-RADIANS($request->long)))")->get();
}else {
$parties = Parties::all();
}
return Fractal::includes('places')->collection($parties,new PartyTransformer);
}
我很好奇如何转换查询以及如何从查询中获取distance_in_km值,因为我想在api响应中显示。
答案 0 :(得分:0)
在原始查询中应用select语句时,将selectRaw替换为whereRaw。
答案 1 :(得分:0)
我修复了问题,这里是代码我希望它会帮助某人:
class PartiesController extends Controller
{
public function index(\Illuminate\Http\Request $request) {
if($request->has('lat') && $request->has('long')){
$lat = $request->lat;
$long = $request->long;
$parties=DB::select(DB::raw("SELECT *,111.045*DEGREES(ACOS(COS(RADIANS(':lat'))*COS(RADIANS(`latitude`))*COS(RADIANS(`longitude`) - RADIANS(':long'))+SIN(RADIANS(':lat'))*SIN(RADIANS(`latitude`)))) AS distance_in_km FROM parties ORDER BY distance_in_km asc LIMIT 0,5"), array(
'lat' => $lat,
'long' => $long
));
$hidacik = Parties::hydrate($parties);
return Fractal::includes('places')->collection($hidacik,new PartyTransformer);
}
else {
$parties = Parties::all();
}
return Fractal::includes('places')->collection($parties,new PartyTransformer);
}
}