我正在尝试获取这些表的总值
building_weight_and_height = {'Floor': ['Roof','10th','9th','8th','7th','6th','5th','4th','3rd','2nd'],
'DL(kN)': [1200,1200,1200,1200,1200,1200,1200,1200,1200,1200],
'StoreyHeight': [3,3,3,3,3,3,3,3,3,4]}
预期产出:
答案 0 :(得分:1)
快速的方法,我相信还有其他方法:
import pandas as pd
dics = {'Floor': ['Roof','10th','9th','8th','7th','6th','5th','4th','3rd','2nd'],
'DL(kN)': [1200,1200,1200,1200,1200,1200,1200,1200,1200,1200],
'StoreyHeight': [3,3,3,3,3,3,3,3,3,4]}
df = pd.DataFrame(columns=['Floor','DL(kN)','StoreyHeight'])
print (df)
df['Floor'] = dics['Floor']
df['DL(kN)'] = dics['DL(kN)']
df['StoreyHeight'] = dics['StoreyHeight']
totalDL = df['DL(kN)'].sum()
totalSH = df['StoreyHeight'].sum()
df=df.append({'Floor':'Total','DL(kN)':totalDL,'StoreyHeight':totalSH},ignore_index=True)
print (df)
输出如下:
Floor DL(kN) StoreyHeight
0 Roof 1200 3
1 10th 1200 3
2 9th 1200 3
3 8th 1200 3
4 7th 1200 3
5 6th 1200 3
6 5th 1200 3
7 4th 1200 3
8 3rd 1200 3
9 2nd 1200 4
10 Total 12000 31
答案 1 :(得分:0)
你有什么问题?
<LinearLayout
android:layout_height="wrap_content"
android:layout_width="fill_parent"
android:orientation="vertical"
>
<RelativeLayout
android:id="@+id/REFReLayTellFriend"
android:layout_width="match_parent"
android:layout_height="wrap_content"
android:orientation="horizontal"
>
<EditText
android:id="@+id/etpass1"
android:layout_width="fill_parent"
android:layout_height="wrap_content"
android:background="@android:color/transparent"
android:bottomLeftRadius="10dp"
android:bottomRightRadius="50dp"
android:fontFamily="@font/frutiger"
android:gravity="start"
android:inputType="textPassword"
android:hint="@string/regpass_pass1"
android:padding="20dp"
android:paddingBottom="10dp"
android:textColor="#000000"
android:textColorHint="#d3d3d3"
android:textSize="14sp"
android:topLeftRadius="10dp"
android:topRightRadius="10dp"/>
<ImageButton
android:id="@+id/imgshowhide1"
android:layout_width="40dp"
android:layout_height="20dp"
android:layout_marginTop="20dp"
android:layout_marginRight="10dp"
android:background="@drawable/showpass"
android:layout_alignRight="@+id/etpass1"/>
</RelativeLayout>
boolean show=true;
//on image click inside password do this
if(show){
imgshowhide2.setBackgroundResource(0);
imgshowhide2.setBackgroundResource(R.drawable.hide);
etpass2.setInputType(InputType.TYPE_TEXT_VARIATION_VISIBLE_PASSWORD);
etpass2.setSelection(etpass2.getText().length());
show=false;
}else{
imgshowhide2.setBackgroundResource(0);
imgshowhide2.setBackgroundResource(R.drawable.showpass);
//etpass1.setInputType(InputType.TYPE_TEXT);
etpass2.setInputType(InputType.TYPE_CLASS_TEXT |
InputType.TYPE_TEXT_VARIATION_PASSWORD);
etpass2.setSelection(etpass2.getText().length());
show=true;
}
答案 2 :(得分:0)
从字典创建数据框,并使用pd.DataFrame.loc
添加一行:
import pandas as pd
building_weight_and_height = {'Floor': ['Roof','10th','9th','8th','7th','6th','5th','4th','3rd','2nd'],
'DL(kN)': [1200,1200,1200,1200,1200,1200,1200,1200,1200,1200],
'StoreyHeight': [3,3,3,3,3,3,3,3,3,4]}
df = pd.DataFrame(building_weight_and_height)
df = df[['Floor', 'DL(kN)', 'StoreyHeight']]
# alternatively:
# df = pd.DataFrame(building_weight_and_height, columns=['Floor', 'DL(kN)', 'StoreyHeight'])
df.loc[len(df.index)+1] = ['Total', df['DL(kN)'].sum(), df['StoreyHeight'].sum()]
print(df)
# Floor DL(kN) StoreyHeight
# 0 Roof 1200 3
# 1 10th 1200 3
# 2 9th 1200 3
# 3 8th 1200 3
# 4 7th 1200 3
# 5 6th 1200 3
# 6 5th 1200 3
# 7 4th 1200 3
# 8 3rd 1200 3
# 9 2nd 1200 4
# 11 Total 12000 31