Question

我正在开发一个数据库/ php项目。数据库中有三个表...一个有roleId和role ..第二个有userId和username ...所以这两个表都有一个用户名和角色的下拉列表...当用户做出选择时，数据应保存在具有roleId和userId的第三个表中。

Table1 : roleId, role
Table2: userId, username
Table3: roleId, userId

怎么做？

这是我到目前为止所尝试的......

<?php

require_once './queries.php';
$roleId = filter_input(INPUT_POST, "roleId");
$userId= filter_input(INPUT_POST, "userId");
$addname = filter_input(INPUT_POST, "addname");
$addrole = filter_input(INPUT_POST, "addrole");
$deletename = filter_input(INPUT_POST, "deletename");
$deleterole = filter_input(INPUT_POST, "deleterole");
$switch = filter_input(INPUT_POST, "switch");

switch ($switch) {
case 'add':
            echo Queries::addRole($roleId, $role);
            break;

}
?>

queries.php

public static function addRole($userId, $roleId) {
       $dbUser = "";
       $dbPass = "";
        $dbConn = "(DESCRIPTION = (ADDRESS = (PROTOCOL=TCP)(HOST=)(PORT=))(CONNECT_DATA=(SID=)))";  
        $conn = oci_connect($dbUser, $dbPass, $dbConn);
        $sql = oci_parse($conn, "INSERT INTO ROLE (roleId, userId) VALUES (:roleid, :userId)");
        oci_bind_by_name($sql,':roleId', $roleId);
        oci_bind_by_name($sql,':userId', $userId);
        oci_execute($sql);

    }

的.js

$("#selectrole").submit(function (event) {

    event.preventDefault();
    $.ajax({
        url: 'functions/role-functions.php',
        type: 'POST',
        data: {"roleId": $('#roleId').val(),"userId": $('#userId').val(),  "switch": "add"},
        dataType: "json",
        success: function () {
            $('#selectdept').trigger('reset');
            $("#userId").val('').trigger('change');
            resultAlert('#adminResult', '#resultAdminContent', '<strong>You data was succefully saved!</strong>', 'alert-success');
        }, error: function () {
            resultAlert('#adminResult', '#resultAdminContent', '<strong>Error! Your data was not saved!</strong>', 'alert-danger');
        }
    });
});

形式

<div class="container">
    <div class="panel panel-default">
        <div class="panel-body">
    <div id="selectrole" class="hide" role="alert">
        <button type="button" class="close" data-dismiss="alert" aria-label="Close"><span aria-hidden="true">&times;</span></button>
        <div id="resultActivityContent"></div>
    </div>  
    <form class="cmxform" id="addroles">
        <legend>Add Roles</legend>
        <label for="names">Select Name</label>
        <select class="form-control" name="names" id="names">
           <option selected disabled></option>
           <?php 
           $dbUser = "";
            $dbPass = "";
            $dbConn = "(DESCRIPTION = (ADDRESS = (PROTOCOL=TCP)(HOST=  )(PORT=  ))(CONNECT_DATA=(SID=  )))"; 
            $conn = oci_connect($dbUser, $dbPass, $dbConn);
            $sql = oci_parse($conn, "SELECT USER.USERNAME  FROM USER");
            oci_execute($sql, OCI_DEFAULT);
            ?>
           <?php
              while (oci_fetch($sql))
                  { ?>
                echo '<option value="<?php echo oci_result($sql, 'USERNAME')?>"><?=oci_result($sql,'USERNAME') ?></option>  
            <?php   
        }?>
        </select>   
        <br>
        <br>
        <label for="role">Select Role</label>
         <select class="form-control" name="role" id="role">
           <option selected disabled></option>
           <?php 
           $dbUser = "  ";
            $dbPass = "  ";
            $dbConn = "(DESCRIPTION = (ADDRESS = (PROTOCOL=TCP)(HOST=  )(PORT=  ))(CONNECT_DATA=(SID=  )))"; 
            $conn = oci_connect($dbUser, $dbPass, $dbConn);
            $sql = oci_parse($conn, "SELECT USERROLE.ROLED FROM USERROLE");
            oci_execute($sql, OCI_DEFAULT);
            ?>
           <?php
              while (oci_fetch($sql))
                  { ?>
                echo '<option value="<?php echo oci_result($sql, 'ROLE')?>"><?=oci_result($sql,'ROLE') ?></option>  
            <?php   
        }?>

        </select> 
        <br>
        <button class="btn btn-info btn-primary" type="submit">Add Role</button>
        <br>
        <br>
    </form>
            </div>
     </div>       
</div>

Answer 1

是的，你可以。我不是PHP开发人员，但我认为第3个表中保存（INSERT）值的操作将由表单中的操作触发。

如果是这样，您应该根据roleId和userId选择role和username为2个变量（例如：v_roleId和v_userId）然后，使用这两个变量执行INSERT into第3个表。

如果没有，请提供更多详细信息，代码部分，您尝试过的所有内容......

我们选择名称时是否可以在数据库中保存数字

1 个答案: